There are 3 atoms present: 1 sodium (Na), 1 oxygen (O), and 1 hydrogen (H).
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
This solution contain 26,3 g NaOH.
98
Sodium hydroxide (NaOH) is polyatomic (contain atoms of Na, O and H).
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
There is one hydrogen atom in one formula unit of NaOH.
Sodium hydroxide is NaOH and contains three atoms, one each of sodium, hydrogen and oxygen.
hydroxide atoms
6
The formula mass of sodium hydroxide, NaOH is 23.0+16.0+1.0=40.0 Amount of NaOH in 25.0g sample = 0.625mol
There are three elements represented here: sodium (Na), oxygen (O), and hydrogen (H). But while there is a such thing as NaOH, I do not belive there is a such thing as Na2OH4
Carbon : 1 Oxygen : 2
208g NaOH
sodium hydroxide is NaOH so its atomic mass is 23+1+16=40 so one mole of NaOH contains 40 grams and 6.023*10^23 molecules hence 10 grams will have 0.25 moles and hence 0.25*6.023*10^23 molecules ==1.0575 *10^23 molcules now 1 molecule of NaOH has 3 atoms so total no of atoms in 10 gram is 1.0575*3*10^23=1.592330625810^23 atoms
.1146g of mass of Unknown and 12.00ml of NaOH. Find the moles of acidic H atoms
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
This is acetic acid which is monobasic acid so one mole of it is neutralized by one mole of NaOH.