stop typing your physics homework in and work it out yourself!
9.2 grams
The gram atomic mass of gold is 196.967 and that of potassium is 39.0983. Therefore, equal numbers of atoms of potassium are supplied by 39.0983/196.967 the mass of potassium compared with gold. 5 X 9.85 = 49.25. This contains the same number of gold atoms as 49.25(39.0983/196.967) or 9.78 grams of potassium contains of potassium atoms, to the justified number of significant digits (limited by the number "9.85", assuming that "5" is intended to be exact.)
8 grams of gold i still 8 grams of gold. so its 8 grams.
a mole of gold weighs 197 grams and there are just over 6E23 atoms in a mole......... that's all you need to know........ now you compute it yourself! Your answer will be correct to at least 2 digits... which is all anyone usually cares about anyway.
A copper sheet is made of... surprise... copper. No gold.
Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag
Gold has a molar mass of 196.96655 grams per mole. 100 grams then is equal to .508 moles which makes 3.059 E23 atoms of gold.
The answer is 9,17233.1023 atoms.
5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================
Quite a few! 197 kilograms gold (1000 grams/1 kg)(1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 6.02 X 1026 atoms of gold ------------------------------------
9.2 grams
equation: g= 175 atoms x 1 mol/6.02x10^23 x 196.97g/1 mol ---> 175 atoms of gold weigh 5.73x10^-20 grams.
Sticking with gold : Gold has an atomic weight of 196.9665 so 196.9665 grams of gold has Avogadro's number of atoms : 6.02 x 10 to the 23 atoms. Use proportions to figure for other weights.
If 3,6 x 10-5 is grams the number of atoms is 1,1.10e17.
12.7 g gold (1 mole Au/197.0 grams)(6.022 X 10^23/1 mole Au) = 3.88 X 10^22 atoms of gold
Well, firstly you need to know if it is pure gold. Assuming that it is, convert the grams to moles 19.7g Au x 1molAu/197.0gAu = 0.1moles Au And then, to get the number of atoms in 0.1 moles of gold, multiply it by Avogadro's number, 6.22x10^23 atoms per mole 0.1mol Au x 6.22x10^23atoms/mole = 6.22x10^22
A gold coin with a diameter of 1 centimeter and a 1 mm thickness has a volume of .07854 cubic centimeters. Gold has a density of 19.30 grams per cubic centimeter. There is 1.5158 grams of gold or 7.7 millimoles or 4.637 E21 atoms.