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How many potassium atoms are present in .01456 grams of potassium?
.01456 g (6.02 x 1023 atoms) / (39.1 g) = 2.24 x 1020 atoms
How many potassium atoms are there in a sample of K2Cr2O7 having a mass of 24.43 g?
The number of potassium atoms is 2,04.10e21.
How many potassium atoms are present in 57.7 g of potassium hexafluoromanganate K2MnF6?
2.81 x 1023 atoms
How many atoms are in the compound KCI?
two elements and two atoms (potassium and chlorine)In one molecule of KCl, there are two elements (potassium and chlorine).The molecular weight of KCl is 74.55 g / mol.So, 74.55 g of KCl will contain 6.023 x 1023 molecules or 12.046 x 1023 atoms.
How many atoms are there in 39 g of potassium?
The atomic mass of potassium is 39 ,therefore the number of mole is 39 /39,which is 1then multiple by Avogadro number you get 6.022*10^24
How many potassium atoms are present in .01456 grams of potassium?
.01456 g (6.02 x 1023 atoms) / (39.1 g) = 2.24 x 1020 atoms
How many potassium atoms are there in a sample of K2Cr2O7 having a mass of 24.43 g?
The number of potassium atoms is 2,04.10e21.
How many potassium atoms are present in 57.7 g of potassium hexafluoromanganate K2MnF6?
2.81 x 1023 atoms
How many atoms are in the compound KCI?
two elements and two atoms (potassium and chlorine)In one molecule of KCl, there are two elements (potassium and chlorine).The molecular weight of KCl is 74.55 g / mol.So, 74.55 g of KCl will contain 6.023 x 1023 molecules or 12.046 x 1023 atoms.
How many grams of potassium are there in 7.20 mol of potassium atoms?
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
How many atoms are there in 39 g of potassium?
The atomic mass of potassium is 39 ,therefore the number of mole is 39 /39,which is 1then multiple by Avogadro number you get 6.022*10^24
What is the atomic symbol for K?
The atomic weight of K (Potassium) is 39.0983 g/mol
How many atoms are in .23 g Pb?
The number of atoms of lead is 6,68.10e23.
How many moles are in 12g of potassium?
12 g of potassium is equivalent to 0,307 moles.
How many atoms are in 49.1740 g of zirconium?
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
How many atoms are in 149 g of calcium?
149 g of calcium contain 22,39.10e23 atoms.
What would have the greatest mass 1 mole of iron atoms 2 moles of oxygen atoms 4 moles of carbon atoms or 1 mole of potassium atoms?
1 mole of iron atoms has the greatest mass - 55,845 g.
