1.12 x 10^22 atoms PFirst determine the number of moles in the 0.577 g sample of phosphorus, determine the number of moles in the sample. Then multiply the moles by 6.022x10^23 atoms/mol.0.577 g P x (1 mol P/30.974 g P) x (6.022x10^23 atoms P/1 mol P) = 1.12 x 10^22 atoms P
78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
156,86.1020 atoms of uranium in 6,2 g uranium
5 g of sulfur contain 0,94.10e23 atoms.
The number of atoms is 28,099.10e23.
1.12 x 10^22 atoms PFirst determine the number of moles in the 0.577 g sample of phosphorus, determine the number of moles in the sample. Then multiply the moles by 6.022x10^23 atoms/mol.0.577 g P x (1 mol P/30.974 g P) x (6.022x10^23 atoms P/1 mol P) = 1.12 x 10^22 atoms P
The number of atoms of lead is 6,68.10e23.
158kg P* 1000g/1 Kg * 1 mol P/30.974 g * 6.022e23 P Atom/mol P = 3.07e27
12 (g) / 31 (g/mol) = 0.387 g / (g/mol) = 0.39 mol of P atoms
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
149 g of calcium contain 22,39.10e23 atoms.
6,687.1023 chlorine atoms
27,30.10e23 atoms
The number of atoms of lead is 6,68.10e23.
78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
156,86.1020 atoms of uranium in 6,2 g uranium
5 g of sulfur contain 0,94.10e23 atoms.