12 (g) / 31 (g/mol) = 0.387 g / (g/mol) = 0.39 mol of P atoms
Remember moles = nass(g) / Mr ( Relative Moleculr Mass) . mass = 120 g Mr =35.5 x 2 = 71 ( Because chlorine exists as a diatomic gas Cl2). Hence moles(Cl2) = 120 /71 = 1.690
Find number of moles of phosphorusmolar mass of phosphorus is 30.97g/moldivide mass by molar mass to get the moles of phosphorus please that your molar mass mast be multiplied by 4 because you have four phosphorus atoms. 30.97*4= 123.88 g/moln= m/M = 62.0g/123.88g/mol= 0.50 molesTheoretically, there are 6 times the number of moles in fluorine than there are in phosphorus because of the ratio 1:6 but fluorine is diatomic gas so we multiply the number of moles by 12 instead of 6. 6 from the ratio times from fluorine being diatomic gas.So 0.5*12=6 moles of fluorine. we multiply that by the molar mass of fluorine multiplied by 12 because we 12fluorine atoms.So, 6= m/228g/mol so to find mass of fluorine we multiply moles times molar mass it gives us 1368g.
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
The number of moles is 4.
Number of moles = weight (in g) / molecular weight = 6.80 / 101.961 = 0.0667 moles or 66.7 milli moles.
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
3,42 moles of phosphorus trichloride have 469,6686 g.
4,70 moles of tetraphosphorus decaoxide contain 582,56 g phosphorus.
120 g calcium is equal to 3 moles.
1.12 x 10^22 atoms PFirst determine the number of moles in the 0.577 g sample of phosphorus, determine the number of moles in the sample. Then multiply the moles by 6.022x10^23 atoms/mol.0.577 g P x (1 mol P/30.974 g P) x (6.022x10^23 atoms P/1 mol P) = 1.12 x 10^22 atoms P
Remember moles = nass(g) / Mr ( Relative Moleculr Mass) . mass = 120 g Mr =35.5 x 2 = 71 ( Because chlorine exists as a diatomic gas Cl2). Hence moles(Cl2) = 120 /71 = 1.690
Find number of moles of phosphorusmolar mass of phosphorus is 30.97g/moldivide mass by molar mass to get the moles of phosphorus please that your molar mass mast be multiplied by 4 because you have four phosphorus atoms. 30.97*4= 123.88 g/moln= m/M = 62.0g/123.88g/mol= 0.50 molesTheoretically, there are 6 times the number of moles in fluorine than there are in phosphorus because of the ratio 1:6 but fluorine is diatomic gas so we multiply the number of moles by 12 instead of 6. 6 from the ratio times from fluorine being diatomic gas.So 0.5*12=6 moles of fluorine. we multiply that by the molar mass of fluorine multiplied by 12 because we 12fluorine atoms.So, 6= m/228g/mol so to find mass of fluorine we multiply moles times molar mass it gives us 1368g.
Find number of moles of phosphorusmolar mass of phosphorus is 30.97g/moldivide mass by molar mass to get the moles of phosphorus please that your molar mass mast be multiplied by 4 because you have four phosphorus atoms. 30.97*4= 123.88 g/moln= m/M = 62.0g/123.88g/mol= 0.50 molesTheoretically, there are 6 times the number of moles in fluorine than there are in phosphorus because of the ratio 1:6 but fluorine is diatomic gas so we multiply the number of moles by 12 instead of 6. 6 from the ratio times from fluorine being diatomic gas.So 0.5*12=6 moles of fluorine. we multiply that by the molar mass of fluorine multiplied by 12 because we 12fluorine atoms.So, 6= m/228g/mol so to find mass of fluorine we multiply moles times molar mass it gives us 1368g.
The number of moles is mass in g/molar mass in g.
The formula is: number of moles = g Be/9,012.
The number of moles 9,92.10e-5.
0.0027 moles.