237g / 28 gmol-1 = 8.46mol. 8.46 x (6.02x1023) = 5.09x1024 silicon atoms.
237 g of Si have 50,818 849 318.10e23 atoms.
Approx 5.082*10^24 atoms.
.250 mole 7.02 ------ 28.09 = .250
78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
156,86.1020 atoms of uranium in 6,2 g uranium
5 g of sulfur contain 0,94.10e23 atoms.
11 g x 1 mol Si/28.0855 g Si= 0.39 mol Si 205g He x 1mol He/4.002602 g He=51.2 mol He
For neptunium 237 (the most stable isotope): 237, 048 173.
.250 mole 7.02 ------ 28.09 = .250
The number of atoms of lead is 6,68.10e23.
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
149 g of calcium contain 22,39.10e23 atoms.
6,687.1023 chlorine atoms
27,30.10e23 atoms
The number of atoms of lead is 6,68.10e23.
78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
5 g of sulfur contain 0,94.10e23 atoms.
156,86.1020 atoms of uranium in 6,2 g uranium
The answer is 3.32*10^23 atoms