Most modern digital cameras use 24 bits (8 bits per primary) to represent a color. But more or less can be used, depending on the quality desired.
Many early computer graphics cards used only 4 bits to represent a color.
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Well, honey, to represent months of the year, you need at least 4 bits because you've got 12 months in a year, and you need 4 bits to represent numbers from 0 to 15. So, technically, you could do it with just 4 bits, but if you want to be fancy, you could use 5 bits for a more efficient representation.
45 in binary is 101101, so you need at least 6 bits to represent 45 characters.
4.1 bit for 2,2 bits for 4,3 bits for 8,4 bits for 16.
If you mean 10 + 6 that's 16 which is 10000 in binary
To represent the days of the week, you would need at least 3 bits. With 3 bits, you can represent up to 8 different values (2^3 = 8), which is sufficient to cover all 7 days of the week (Monday to Sunday). Each additional bit would double the number of possible values, but 3 bits are the minimum required to uniquely represent all 7 days.
"recommended setting" There are 19 characters including the space between the two words. If the old convention of using 1 byte to represent a character, then we would need (19 x 8) which is 152 bits. If we use unicode as most modern computers use (to accommodate all the languages in the world) then 2 bytes will represent each character and so the number of bits would be 304.
To determine the number of bits in three dollars, we need to first convert the dollar amount to cents, as there are 100 cents in a dollar. Three dollars is equal to 300 cents. Next, we need to calculate the number of bits in 300 cents. Since 2^8 (256) is the closest power of 2 to 300, we would need at least 8 bits to represent 300 cents accurately.
You need four bits for each hex digit since 4 bits can support a value from 0-15. Binary_____Hexidecimal 0_________0 1_________1 10________2 11________3 100_______4 101_______5 110_______6 111_______7 1000______8 1001______9 1010______A 1011______B 1100______C 1101______D 1111______F
Bit -- Value 1 -- 1 11 -- 3 111 -- 7 1111 -- 15 11111 -- 31 111111 -- 63 1111111 -- 127 11111111 -- 255 111111111-- 511 1111111111 -- 1023 Therefore - 10 bits would be more than adequate (unless you had to represent capitals and lower case - in which case you would need one more bit).
You need 20 bits of address bus to address 1 Mb of memory.
You would need 6 colours, one for each of: adenine, thymine, guanine, cytosine, phosphate and deoxyribose.