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in sodium chloride chlorine gains an electron and the bond formed between then is ionic.
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The balanced reaction between sodium and chlorine is as follows Na + Cl =>Na+ + Cl-. In this reaction, sodium loses an electron to sodium. Note that the products of this reaction are ions in the solid state.
Valence electron - Sodium loses one electron to form a sodium ion (valence of 1).
Chlorine is extremely electronegative and will steal electrons from the valence shell of sodium. When chlorine steals the electron, both sodium and chlorine have full valence shells.
Only one, from sodium to chlorine.
An ionic bond as there is an actual transfer of electrons between the two elements in the product, Sodium Chloride. Sodium gives away one electron in order to become stable, i.e., get noble gas configuration and chlorine accepts that electron (given away by Sodium) to become stable. Thus, an ionic bond is formed between them.
Sodium has 1 electron to "donate" and chlorine has space to "accept" 1 electron, so this electron transfer occurs and both have a stable octet electron configuration
in sodium chloride chlorine gains an electron and the bond formed between then is ionic.
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ionic bond
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A sodium ion is a sodium atom missing one electron. A chlorine ion is a chlorine atom with an extra electron. A salt molecule is a sodium ion stuck to a chlorine ion.
The sodium atom, Na, is ionized, giving it's electron to the chlorine, Cl. Therefore, one electron is transferred from the sodium to the chlorine, forming Na+ and Cl- ions and an ionic bond.
Sodium would lose one electron and chlorine would gain one electron. End of contest. Sodim is oxidised, chlorine is reduced.