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Ab and ab

There would be about a 50/50 ratio of each.

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13y ago
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12y ago

one type of gamete will be formed having genotype Ab

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11y ago

2 can

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Q: What are all the possible gametes of an individual with the genotype Aabb?
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How many different kinds gametes will an individual with genotype AAbb produce?

2 can


An individual with the genotype AaBb produces four different gametes in equal proportions This is a demonstration of?

law of independent assortment b


In the individual with genotype AaBB what percentage of gametes will contain the A allele?

You need to make a Punnet Square Put A and a on top and B and B on the left side. These represent the possible gametes. Your results should be: AB AB Ba (aB) Ba (aB) So 50% of the genotype have the A allele.


What will the percentage of a b gametes produced by Aa Bb parent?

If the genotype is AaBb then there will be 4 gametes produced: AB, Ab, aB, ab. Therefore the percentage of ab gametes is 25%


What is a heterozygous genotype for a dihybrid?

AaBb usually, but can also be AAbb or aaBB depending on what they ask you is heterozygous. To be heterozygous for one trait, it's AaBb. To have a heterozygous genotype, unless specified, it can be any of the above.


An individual with a genotype of Aa Bb CC is able to produce how many different kinds of gametes?

Each time a gamete is formed, one allele from each gene (i.e. either A or a) is included.This means for an individual with AaBbCc, there are 8 different gametes:ABCABcAbCAbcaBCabCaBcabc


How many gametes in AaBB?

4


Where did the ratio 9331 come from include what each of these four numbers mean?

The 9/3/3/1 ration is the ratio of phenotypes that are the result of a dihybrid cross. Consider two genes, A and B, that reside on different chromosomes (so that they independently assort). Assume each gene has two alleles. For A, A is dominant and a is recessive, while for the B gene, B is dominant and b is recessive. Now consider a cross between two individuals that are heterozygous for both genes (this is called a dihybrid cross): AaBb X AaBb There are only 4 possible gametes that each individual can produce (in equal proportion): AB Ab aB ab So if we cross the two we get 16 combinations. This will result in 9 possible genotypes: AABB AABb AAbb AaBB AaBb Aabb aaBB aaBb aabb However, there are only 4 possible phenotypes (with proportion in parentheses): Dominant A and B (9/16) (AABB, AABb, AaBB, AaBb) Dominant A, Recessive B (3/16) (AAbb, Aabb) Recessive A, Dominant B (3/16) (aaBB, aaBb) Recessive A, Recessive B (1/16) (aabb)


What color is a person with AAbb genotype?

if a man were non- hemophiliac and he marries a woman whois homozygus for nan-hemophilia,give the possible genotypes of the children


What are the possible gametes for AAA AAA?

A gamete is haploid (1N) so 'Aa' & 'AA' are diploid and during cell division (mitosis) gametes are formed and then 2 gametes merge together to make a diploid (think of sperm and egg, each is haploid or 1N, when fertilization occurs the egg and sperm form 1 cell that is 2N or diploid). So the possible gametes for 'Aa' would be 'A' & 'a' while for 'AA' the only gametes possible are 'A' If the question is asking what the possible gametes are for 'AaBB' the haploid (gamete) can be 'AB' or 'aB'


What word describes an organism that has the genotype Bb?

The most accurate description of an organism with genotype AaBb is heterozygous. A homozygous genotype is aaBB and AA.


What two types of gametes could result from AABb allele combination?

The two types of gametes that could result from the AABb allele combination are AB and Ab. This is because during meiosis, homologous chromosomes separate and randomly assort, leading to different combinations of alleles in gametes.