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The atomic weight of K is 39.098 and so 0.180 moles would be:
39.098 x 0.180 = 7.038 g to 3 decimal places.
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∙ 13y ago
To find the number of grams in 0.180 moles of potassium (K), you would first need to determine the molar mass of potassium, which is approximately 39.10 g/mol. Then, you can use the formula: grams = moles x molar mass. Therefore, 0.180 moles of K would be equal to approximately 7.02 grams (0.180 mol x 39.10 g/mol).
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What is the mass of potassium chloride when 6.75 g of potassium reacts with an excess of chlorine gas?
Balanced equation and potassium limits and drives the reaction.2K + Cl2 -> 2KCl6.75 grams K (1 mole K/39.10 grams)(2 mole KCl/2 mole K)(74.55 grams /1 mole KCl)= 12.9 grams potassium chloride produced==============================
How many protons are in 4.78g of K?
To find the number of protons in 4.78g of potassium (K), first calculate the number of moles of K using its molar mass (39.10 g/mol). Then, since potassium has 19 protons in each atom, multiply the number of moles by Avogadro's number (6.022 x 10^23 mol^-1) to get the number of protons.
What is the amount percentage of manganese in potassium permanganate KMnO4?
Manganese makes up about 31.65% of the molecular weight of potassium permanganate (KMnO4).
How many moles of oxygen gas can 0.88 mole of hydrogen peroxide produce if decomposition is complete?
For the decomposition of hydrogen peroxide, 1 mole of hydrogen peroxide (H2O2) yields 1 mole of oxygen gas (O2). Therefore, 0.88 mole of H2O2 will produce 0.88 mole of O2 if the decomposition is complete.
Which would have a higher mass a mole of K atoms or a mole of Au atoms?
A mole of Au atoms would have a higher mass compared to a mole of K atoms because gold (Au) atoms have a larger atomic mass than potassium (K) atoms. The molar mass of a substance is determined by adding the atomic masses of the individual atoms in the mole.
How many protons are in 4.78g of K?
To find the number of protons in 4.78g of potassium (K), first calculate the number of moles of K using its molar mass (39.10 g/mol). Then, since potassium has 19 protons in each atom, multiply the number of moles by Avogadro's number (6.022 x 10^23 mol^-1) to get the number of protons.
What is the mass of potassium chloride when 6.75 g of potassium reacts with an excess of chlorine gas?
Balanced equation and potassium limits and drives the reaction.2K + Cl2 -> 2KCl6.75 grams K (1 mole K/39.10 grams)(2 mole KCl/2 mole K)(74.55 grams /1 mole KCl)= 12.9 grams potassium chloride produced==============================
How many grams of potassium are there in 7.20 mol of potassium atoms?
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
How many atoms are in 3.50 moles of calcium?
There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K. Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24
How do you find the mass of a sample of 1.72 x 1023 atoms of potassium?
1 mole K atoms = 39.0983g K (atomic weight in grams)1 mole K atoms = 6.022 x 1023 atoms K (Avogadro's number)Convert known atoms to moles.1.72 x 1023 atoms K x (1mol K/6.022 x 1023 atoms K) = 0.286mol KConvert moles to mass in grams.0.286mol K x (39.0983g K/1mol K) = 11.2g K
How many atoms are in 0.0602 mol K?
0.0602 mole K x 6.02x10^23 atoms/mole = 3.62x10^22 atoms
What is the molarity of a 5.00x 10 2ml solution containing 249g of k?
Molarity = moles of solute/Liters of solution some conversion needed 5.00 X 102 ml = 0.5 liters ------------------------------------- 249 grams K (1 mole K/39.10 grams = 6.37 moles potassium ------------------------------------------------------------------------------- Molarity = 6.37 mole K/0.5 Liters = 12.7 M K -----------------( as expected, highly concentrated solution )
How many grams of KO2 would be required to produce 1120.0L of O2 at 20.0 degrees Celsius and 1.00atm?
To determine the amount of KO2 required to produce 1120.0 L of O2 at 20.0°C and 1.00 atm, we need to use the ideal gas law. First, calculate the moles of O2 using PV = nRT. Then, use the balanced chemical equation for the decomposition of KO2 to O2 to find the molar ratio and the mass of KO2 needed.
How many grams of potassium are in 24.1 g of K2Cr2O7?
To find the amount of potassium in K2Cr2O7, we need to determine the molar mass of K2Cr2O7 and the molar mass of potassium. Molar mass of K2Cr2O7 = (239.10 g/mol) + (252.00 g/mol) + (7*16.00 g/mol) = 294.18 g/mol Molar mass of potassium = 39.10 g/mol Now, determine the amount of potassium in 24.1 g of K2Cr2O7 by first converting 24.1 g of K2Cr2O7 to moles, then calculating the grams of potassium is in that amount of K2Cr2O7 using the molar ratios determined by the chemical formula.
How many potassium atoms are in 0.0384 mole K?
0.0384 moles K x 6.02x10^23 atoms/mole = 2.31x10^22 atoms
How can you convert Meq to Mg?
fo potassium 60 mEq K = 60 millimoles 39.1 grams per mole ( 0.060moles) = 2.346 grams =2346 mg
How many grams in a k cup?
approximately 1.5 grams.
