The molecular weight of sodium (Na) is 22.99 grams. The molecular weight of chlorine (Cl) is 35.45 grams. Therefore, there are 58.44 grams in 1 mole of NaCl. So, in 3.25 moles of NaCl, there are 58.44 gr x 3.25 = 189.93 grams.
Keeping it simple:
1 Mole of NaCl= 58 grams
58 x 2.5= 145 grams
The answer is 175,319 g.
The answer is is 131,49 g.
The answer is 187,007 g.
The answer is 146,1 g.
The answer is 146,1 g NaCl.
The answer is 0,428 moles.
there is .42 moles
For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaCl=58 grams 25.0 grams NaCl / (58 grams) = .431* moles NaCl *approximation
Sr is 87.6g/mol, and 25/87.6 = 0.285 moles.
.071 moles
800 g oxygen are needed.
25 moles of sulfur dioxidecontain 800,825 g oxygen.
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
Use stoichiometry. 3.5g-> moles 22.99+16+1.0079=39.99 Now 3.5/39.99 = .088 moles of NaOH Now you can use avagadros number 6.022x10^23 .088 moles -> formula units .088/6.022x10^23 You should end up with 1.46x10-25 formula units. Yeah, I know, Chem sucks huh?
5 moles of lead is equal to 1 036 g.
The formula mass of sodium hydroxide, NaOH is 23.0+16.0+1.0=40.0 Amount of NaOH in 25.0g sample = 0.625mol
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
The answer is 29,22 g NaCl.