I assume you mean 6.2 x 1022, but the logic is the same for other amounts anyway.
6.2 x 1022 atoms is 0.01295 moles (using Avogadro's number)
1 mole gold weights 197 grams (many periodic tables list this in the top right corner)
Therefore your gold weights 197 x 0.01295 = 2.6 g
You divide 1.204x10^24 by avagadros number to get the amount of moles. Dividing by 6.022x10^23 gives you 2 moles. Moles is mass / molecular mass. The Atomic Mass of gold is 196.97g/mol so this is 393.94g.
4.95 x 1022 atoms Au (196.97 g / 6.02 x 1023 at) = 16.2 grams Au
Gold has a molar mass of 196.96655 grams per mole. 100 grams then is equal to .508 moles which makes 3.059 E23 atoms of gold.
5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================
The answer is 28,0987.1023 atoms.
7,5.1021 uranium atoms = 2,9644 grams
2.936*10^24 atoms....
The answer is 9,17233.1023 atoms.
Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag
Gold has a molar mass of 196.96655 grams per mole. 100 grams then is equal to .508 moles which makes 3.059 E23 atoms of gold.
5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================
9.2 grams
Quite a few! 197 kilograms gold (1000 grams/1 kg)(1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 6.02 X 1026 atoms of gold ------------------------------------
stop typing your physics homework in and work it out yourself!
If 3,6 x 10-5 is grams the number of atoms is 1,1.10e17.
12.7 g gold (1 mole Au/197.0 grams)(6.022 X 10^23/1 mole Au) = 3.88 X 10^22 atoms of gold
How many grams are in an oz of gold?
25,1 grams sulfur contain 4,7147765.10e23 atoms.
Well, firstly you need to know if it is pure gold. Assuming that it is, convert the grams to moles 19.7g Au x 1molAu/197.0gAu = 0.1moles Au And then, to get the number of atoms in 0.1 moles of gold, multiply it by Avogadro's number, 6.22x10^23 atoms per mole 0.1mol Au x 6.22x10^23atoms/mole = 6.22x10^22