I assume you mean 6.2 x 1022, but the logic is the same for other amounts anyway.
6.2 x 1022 atoms is 0.01295 moles (using Avogadro's number)
1 mole gold weights 197 grams (many periodic tables list this in the top right corner)
Therefore your gold weights 197 x 0.01295 = 2.6 g
You divide 1.204x10^24 by avagadros number to get the amount of moles. Dividing by 6.022x10^23 gives you 2 moles. Moles is mass / molecular mass. The Atomic Mass of gold is 196.97g/mol so this is 393.94g.
4.95 x 1022 atoms Au (196.97 g / 6.02 x 1023 at) = 16.2 grams Au
Gold has a molar mass of 196.96655 grams per mole. 100 grams then is equal to .508 moles which makes 3.059 E23 atoms of gold.
5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================
The answer is 28,0987.1023 atoms.
7,5.1021 uranium atoms = 2,9644 grams
2.936*10^24 atoms....
Gold has a molar mass of 196.96655 grams per mole. 100 grams then is equal to .508 moles which makes 3.059 E23 atoms of gold.
There are approximately 1.93 x 10^23 atoms in 300 grams of gold. This is calculated using Avogadro's number (6.022 x 10^23 atoms/mole) and the molar mass of gold (197 grams/mole).
There are approximately 7.60 x 10^21 atoms of gold in 5 grams of gold. This calculation is based on the molar mass of gold (197 g/mol) and Avogadro's number (6.022 x 10^23/mol).
5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================
Every drop of seawater contains around 0.12 billion gold atoms.
There would be approximately 1.86 x 10^21 atoms in one kilogram of gold. This calculation is done by taking the mass of gold in a kilogram (1000 grams) and dividing by the mass of one gold atom (3.27x10^-22 grams) to find the number of atoms.
stop typing your physics homework in and work it out yourself!
To calculate the number of atoms in 197 kg of gold, you would first convert the mass of gold to moles using the molar mass of gold, which is approximately 197 g/mol. Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms in the moles of gold.
There are approximately 31.1 grams in 1 ounce of gold.
25,1 grams sulfur contain 4,7147765.10e23 atoms.
A gold coin typically contains billions of atoms, as gold is a dense metal with a high atomic number (79). The exact number of atoms in a gold coin would depend on its size and weight, but it would be in the order of 10^22 atoms.
To find the number of atoms in the gold ring, you need to convert the mass of the ring to moles using the molar mass of gold (197 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of atoms in the ring. So, for a mass of 19.7 grams of gold, you would have approximately 3.0 x 10^22 atoms.