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5.10 grams phosphorous (1 mole P/30.97 grams)(6.022 X 10^23/1 mole P) = 9.92 X 10^22 atoms of phosphorous
What is the mass, in grams, of 2 × 1012 atoms of potassium?
25,1 grams sulfur contain 4,7147765.10e23 atoms.
Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag
Simple: the atomic weight expressed in grams. Example for dysprosium - 162,500 grams.
4.00
1 gram phosphorus (1mol P/30.97 grams)(6.022 X 10^23/1mol P) = 1.9 X 10^22 atoms of phosphorus
5.10 grams phosphorous (1 mole P/30.97 grams)(6.022 X 10^23/1 mole P) = 9.92 X 10^22 atoms of phosphorous
By saying Avogadro's number of atoms, you are saying one mole (or 6.02 × 1023 atoms). And one mole of any elements is its atomic mass. Phosphorus' atomic mass is 31.0 grams
In Grams, A TV could weigh about 10-50 grams.
The daily requirement of phosphorus is 800. How many grams of phosphorus are needed?
Mass. 6.3 X 10^21 atoms phosphorous (1 mole P/6.022 X 10^23)(30.97 grams/1 mole P) = 0.32 grams of phosphorous -------------------------------------
2,88 grams of helium have 3,761.1023 atoms; 16,4 grams of zinc have 1,511.1023 atoms.
Quite a few! 392 grams phosphorous (1 mole P/30.97 grams) = 12.7 moles phosphorous ===================
2.3 grams P (1mole P/30.97 grams) = 0.07427 moles Phosphorous 0.07427 moles P * 6.022 X 10^23 = 4.5 X 10^22 atoms of P in 2.3 grams P 4.5 X 10^22/6.022 X10^23 = 0.07427 moles of atoms in 2.3 grams of phosphorous
Helium because it has fewer atoms, so there are more atoms needed to have 3.5 grams of it.
What is the mass, in grams, of 2 × 1012 atoms of potassium?