2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Ag
3.82 mole * 107.9 g/mole = 412 g Ag
(2.3 x 1024 atoms Ag) x (1 mole Ag/ 6.022 x 1023 atoms Ag) x (107.0 g Ag/ 1 mole Ag) = 412.1056 g Ag
Convert the atoms Ag to moles of silver. Then convert the moles to grams.
There are 6.022*10+23 particles (eg. atoms) in one mole, thus:
2.3*10+24 / 6.022*10+23 = 38.19 = 38 moles Ag-atoms
2.3 x 1024 atoms Ag * (1 mol Ag/ 6.022 x 1023 atoms Ag)*(107.9 g Ag/mol Ag) =
412.1 g of Ag
2.31024 atoms? this doesnt make sense...
if you mean 2,31024 moles, then m= Ar(Ag) x 2,31024= 249,01 g
2.3 X 1024 atoms of silver (1 mole Ag/6.022 X 1023)(107.9 grams/1 mole Ag)
= 412 grams silver
==============
1 mole Ag = 107.8682g = 6.022 x 1023 atoms
1.80 x 1023 atoms Ag x (107.8682g)/(6.022 x 1023 atoms) = 32.2g Ag
grams = 7.4 x 1024 x (Atomic Mass of silver) / (6.023 x 1023)atomic mass of silver = 107.868
Answer = 1325.2917 grams
6,022140857.1023 atoms--------------------------107,8682 g
7,4.1024 atoms-----------------------------------------x
x = 1325,48 g
The answer is 28,0987.1023 atoms.
7,5.1021 uranium atoms = 2,9644 grams
16.3 grams ÷ 32.1 grams × (6.02 × 1023) = 3.06 × 1023 atoms S
Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C
I think you meant 3.09x10^24 atoms of sulfur. 3.09x10^24 atoms * (1 mol / 6.02x10^32 atoms) * (32 g / 1mol) = 165 grams
2.3 X 1024 atoms / 6.022 X 1023 atoms/mole X 107.87 gm/mole of silver = 412 grams
10.8 grams silver (1 mole Ag/107.9 grams)(6.022 X 1023/1 mole Ag) = 6.03 X 1022 atoms of silver =====================
3.76 grams silver (1 mole Ag/107.9 grams)(6.022 X 10^23/1 mole Ag) 2.10 X 10^22 atoms of silver ---------------------------------------
3.68 grams silver (1 mole Ag/107.9 grams)(6.022 X 10^23/1 mole Ag) = 2.05 X 10^22 atoms of silver -----------------------------------------
To find the number of atoms in a sample of silver, we first need to convert the mass from pounds to grams. Then we calculate the number of moles of silver using the molar mass of silver. Finally, we use Avogadro's number to convert moles to atoms. The answer would be approximately 2.0 x 10^23 atoms in a 0.84 lb sample of silver.
2.09*10^22 This is how you figure it out: 3.74g divided by 107.87(the atomic mass of silver). Then you multiply the number you get by 6.022x10^23 (Avogadros number). And that's your answer.
Using your molar mass. 0.0001 grams silver (1 mole Ag/108 grams)(6.022 X 1023/1 mole Ag) = 5.58 X 1017 atoms of silver =====================
4.563kg
2,88 grams of helium have 3,761.1023 atoms; 16,4 grams of zinc have 1,511.1023 atoms.
To find the number of silver atoms in 3.88 g of silver, you can use the formula: Number of atoms = (mass in grams / molar mass) x Avogadro's number The molar mass of silver is 107.87 g/mol, and Avogadro's number is 6.022 x 10^23 mol^-1. Therefore, there are approximately 8.59 x 10^22 silver atoms in 3.88 g of silver.
I assume you mean 3.55 grams of silver. Don't forget your units! Silver (Ag, #47) has an atomic mass of about 108 grams per mole. Set up a direct proportion: 108/1=3.55/x, where x is the unknown number of moles in 3.55 grams Ag. Solve for x to get approx. 0.033 moles Ag. Multiply this number by Avogadro's constant of 6.02x1023 to get the number of representative particles. So, 0.033(6.02x1023)=1.99x1022 atoms of silver.
According to the periodic table, silver (Ag) has an atomic mass of about 108 grams per mole. If you have 802 grams, set up a direct proportion where 108/1=802/x and solve for x. You get about 7.43 moles of silver.