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10 grams lead (1 mole Pb/207.2 grams)(6.022 X 1023/1 mole Pb)

= 2.9 X 1022 atoms of lead

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What is the mass of 6.25x1020 atoms of lead?

The molar mass of lead (Pb) is 207.2 g/mol. To find the mass of 6.25x10^20 atoms, you need to divide the number of atoms by Avogadro's number (6.022x10^23) to get the number of moles, then multiply by the molar mass of lead. The mass of 6.25x10^20 atoms of lead is approximately 1.72 grams.


How many grams of lead is needed to equal the number of atoms contained in 10 grams of tin?

Let us do this in two parts for clarity. Find atoms in tin first. 10 grams tin (1 mole Sn/118.7 grams)(6.022 X 1023/1 mole Sn) = 5.07 X 1022 atoms of tin ----------------------------------- 5.07 X 1022 atoms (1 mole Pb/6.022 X 1023)(207.2 grams/1 mole Pb) = 17 grams of lead ------------------------------ I can see two other ways to do the conversion string, one longer and one much shorter. See if you can find them.


How many atoms are there in 80 grams of lead?

To calculate the number of atoms in 80 grams of lead, you first need to determine the number of moles of lead using its molar mass (207.2 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms. So, for lead, there are approximately 3.86 x 10^23 atoms in 80 grams.


What is the mass of lead?

Lead (Pb) has the atomic number 82 with an Atomic Mass of 207.2 amu.


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What is the mass in grams of 1.00 X 1012 lead (Pb) atoms?

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There are approximately 1.93 x 10^23 atoms in 300 grams of gold. This is calculated using Avogadro's number (6.022 x 10^23 atoms/mole) and the molar mass of gold (197 grams/mole).


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