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The Atomic Mass of potassium is 39.10 g/mol.
1.90 mol K * (39.10 g K / 1 mol K) = 74.3 g K
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How many grams of KO2 would be required to produce 1120.0L of O2 at 20.0 degrees Celsius and 1.00atm?
Use.PV = nRTTo get moles O2. ( 20.0o C = 293.15 Kelvin )(1.00 atm)(1120.0 L) = (X moles)(0.08206 L*atm/mol*K)(293.15 K)Moles = 1120.0/24.56= 45.60 moles O2-----------------------------------now,45.60 moles O2 (1 mole KO2/2 mole O2)(71.1 grams/1 mole KO2)= 1621 grams potassium oxide required=============================
How many grams are in 0.180 mole of K?
The atomic weight of K is 39.098 and so 0.180 moles would be: 39.098 x 0.180 = 7.038 g to 3 decimal places.
How many moles are in 3.3 moles of K2S?
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
How many moles of K are in 1.000 g of K4Fe(CN)6?
The answer is 0,0108 moles.
How many moles of air are there in a 3 L container at 1 ATM pressure of 293 K?
0,125 moles
Which equivalence factor should you use to convert from 38.2 grams of K to moles of K?
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How many moles in 284 grams of potassium?
Potassium has atomic number 39.1.Amount of K in 284g sample = 284/39.1 = 7.26molThere are 7.26 moles of potassium in a 284g sample.
How many grams of KO2 would be required to produce 1120.0L of O2 at 20.0 degrees Celsius and 1.00atm?
Use.PV = nRTTo get moles O2. ( 20.0o C = 293.15 Kelvin )(1.00 atm)(1120.0 L) = (X moles)(0.08206 L*atm/mol*K)(293.15 K)Moles = 1120.0/24.56= 45.60 moles O2-----------------------------------now,45.60 moles O2 (1 mole KO2/2 mole O2)(71.1 grams/1 mole KO2)= 1621 grams potassium oxide required=============================
How many grams of potassium are there in 7.20 mol of potassium atoms?
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
How many grams are in 0.180 mole of K?
The atomic weight of K is 39.098 and so 0.180 moles would be: 39.098 x 0.180 = 7.038 g to 3 decimal places.
How many grams are there in 3.3 moles of potassium sulfide?
The atomic mass of Potassium is 39 and that of Sulfur 32. The formula for Potassium Sulfide is K2S therefore the molecular weight of Potassium Sulfide is (39 * 2) + 32 = 110. Therefore one mole of Potassium Sulfide weighs 110 grams. Therefore 3.3 moles of Potassium Sulfide weigh 110 * 3.3 = 363 grams.
How many moles are in 3.3 moles of K2S?
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
How many moles of K are in 1.000 g of K4Fe(CN)6?
The answer is 0,0108 moles.
How do you find the mass of a sample of 1.72 x 1023 atoms of potassium?
1 mole K atoms = 39.0983g K (atomic weight in grams)1 mole K atoms = 6.022 x 1023 atoms K (Avogadro's number)Convert known atoms to moles.1.72 x 1023 atoms K x (1mol K/6.022 x 1023 atoms K) = 0.286mol KConvert moles to mass in grams.0.286mol K x (39.0983g K/1mol K) = 11.2g K
What is the molarity of a 5.00x 10 2ml solution containing 249g of k?
Molarity = moles of solute/Liters of solution some conversion needed 5.00 X 102 ml = 0.5 liters ------------------------------------- 249 grams K (1 mole K/39.10 grams = 6.37 moles potassium ------------------------------------------------------------------------------- Molarity = 6.37 mole K/0.5 Liters = 12.7 M K -----------------( as expected, highly concentrated solution )
How many atoms are in 0.3 moles of potassium?
0.3 moles K (6.022 X 10^23/1mol K) = 1.8 X 10^23 atoms of K
How many moles are there in a 3 L container at 1 ATM pressure and 293 K?
The answer is 0,125 moles.
