Density of H2 in liquid is 0.07099 g/L
so 31.6 ml = 0.0316 Liters
0.07099 g/L = mass in grams/0.0316 Liters
= 2.24 X 10^-3 grams
Yes.
This is based on calculations. It contains 25 grams of H2.
The number of molecules is 6,3985.10e24.
34 grams of Ammonia
9g Al x (1 mol Al/27g Al) x (3mol H2 / 2 mol Al) x (22.4L / 1 mol H2) = 11.2L H2
Yes.
This is based on calculations. It contains 25 grams of H2.
The answer is 20,664 g ammonia.
34 grams of Ammonia
The number of molecules is 6,3985.10e24.
None. There is no hydrogen in sodium
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
9g Al x (1 mol Al/27g Al) x (3mol H2 / 2 mol Al) x (22.4L / 1 mol H2) = 11.2L H2
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
Balanced equation. 2H2 + O2 --> 2H2O 5 moles H2 (2 moles H2O/2 mole H2)(18.016 grams/1 mole H2O) = 90 grams of water ===============
The mass of ammonia is 147,5 g.