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How many grams of NaCl are present in 8.39x10^22 formula units of NaCl?

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6y ago
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6y ago

3.39x10^22 formula units x 1 mole/6.02x10^23 formula units x 23 g/mole = answer

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Q: How many grams of NaCl are present in 8.39x1022 formula units of NaCl?
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How many NaCl formula units make up 0.11 grams of salt crystals?

The number of formula units of NaCl is 11335.10e17.


How many grams of oxygen are in 1.851023 formula units of (NH4)2SO4?

This mass is 244,459.10e23 g.


How many molecules are in 7.4 g H'S?

By definition, Avogadro's Number is the number of molecules or formula units in the number of grams corresponding to the gram molecular weight or gram formula unit, and by experiment, Avogadro's Number is about 6.022 X 1023. Therefore, 7.75 X 1025 formula units contains (7.75 X 1025/6.022 X 1023) or 1.29 X 102 moles or formula units, to the justified number of significant digits.


How many GRAMS of aluminum carbonate are present in 7.01E 22 formula units of this compound?

Aluminum carbonate is Al2(CO3)3. If you have 7.0x1022 particles of it, then that's 7.0x1022/6.02x1023 = 0.116 moles. The compound has a molar mass of 234g/mol, so 234x0.116=27.144 grams.


How much magnesium sulphide can be made from 1.0gram of magnesium and 1.0gram of sulphur?

The formula of magnesium sulphide is MgS, showing that a formula unit has one atom of each element. The gram atomic mass of magnesium is 24.305 and that of sulphur is 32.06. Therefore, when magnesium and sulphur are present in equal amounts by mass, sulphur is the limiting reactant. 1.0/32.06 or 0.031 moles of sulphur atoms are present. Therefore, the maximum amount of MgS that can result from reaction is 0.031 formula units of MgS. The gram formula mass of MgS is 56.365, so that 0.031 formula units of MgS will have a mass of 1.7 grams, to the justified number of significant digits.

Related questions

How many formula units of AgNO3 are present in 147g of this compound?

The answer is 5,21131981201352.10e23 formula units of silver nitrate.


How many NaCl formula units make up 0.11 grams of salt crystals?

The number of formula units of NaCl is 11335.10e17.


How many formula units are in 32.6 grams of potassium oxide?

K2O is potassium oxide. Formula mass = 94g32.6 g x 1 FU/94 g = 0.35 formula units


How many formula units in 32.6 grams of potassium oxide?

K2O is potassium oxide. Formula mass = 94g32.6 g x 1 FU/94 g = 0.35 formula units


How many grams of salt are in 3.23x1023?

31,35 g in 3,23.1023 molecules (formula units).


How many formula units of LiCl are equal to .648 moles?

42.394 grams.


What are the moles conversion formulas involving grams and formula units?

FORMULA UNITS TO MOLES (formula units --> moles)Divide the number of formula units by Avogadro's number.----------- Formula UnitsAvogadro's number (formula units)Conversion FactorFormula Units x 1 mol-------- Avogadro's number (formula units)MOLES TO FORMULA UNITS (moles --> formula units)Multiply the number of moles by Avogadro's number.Moles Substance x Avogadro's numberConversion FactorMol substance x Avogadro's number---------------------- 1 mol substanceMOLES TO GRAMS (moles --> grams)*Multiply the number of moles by the substance's molar mass.Moles Substance x Molar Mass SubstanceConversion FactorMol Substance x Molar Mass Substance------------------------- 1 mol SubstanceGRAMS TO MOLES (grams --> moles)*Divide the number of grams by the substance's molar mass.---- Mass (g) SubstanceMolar Mass (g) SubstanceConversion FactorMass (g) Substance x 1 mol substance----------------------- Molar Mass Substance (g)FORMULA UNITS TO GRAMS (formula units --> moles --> grams)*Divide formula units by Avogadro's number (6.022 x 1023 formula units); multiply by molar mass.--- Formula Units --- x --- Molar MassAvogadro's numberConversion FactorFormula Units x 1 mol ----------------- x -------------- Molar mass (g)---------- Avogadro's number (formula units) ----------- 1 molGRAMS TO FORMULA UNITS (grams --> moles --> formula units)*Divide mass of substance by the molar mass of substance; multiply by Avogadro's number.---- Mass (g) substance -- x -- 6.022 x 1023 moleculesMolar mass (g) substanceConversion Factor--- Mass substance (g) x 1 mol substance ------ x ----- Avogadro's number------------------------ Molar Mass (g) substance ----------- 1 mol substanceTip: On test day, anytime you see the words ions, formula units, molecules, or atoms on a question, that problem will involve the usage of Avogadro's number.*Finding Molar Mass# Atoms Element A x Atomic Mass Element A (Periodic Table) = mass (g) El. A# Atoms Element B x Atomic Mass Element B (Periodic Table) = mass (g) El. B... etc.Add up all the mass values found above and you have molar mass.


How many grams of oxygen are in 1.851023 formula units of (NH4)2SO4?

This mass is 244,459.10e23 g.


How many formula units of MgCl2 are found in 125.25 grams of the compound?

molar mass of MgCl2= 95.2195.21/125.25=0.76 mole1 mole would have 6.02x1023 formula units so 0.76 moles would have0.76 x (6.02x1023)= 4.575x1023 formula units.


Grams to formula units?

It depends on the substance and its molar mass.In order to convert from grams to formula units, you must first convert grams to moles, then moles to formula units (grams --> moles --> formula units).1. Divide the mass (g) of the given substance by the substance's molar mass.2. Multiply the number of moles found in Step 1 (above) by Avogadro's number (6.022 x 1023).---- Mass substance ----- X 6.022 x 1023 formula unitsMolar mass substanceCONVERSION FACTORMass (g) substance x 1 mol substance ------- x ----- Avogadro's number/////////////////// molar mass (g) substance ------------ 1 mol substance


How many formula units in 47.63 grams?

It depends on the substance and its molar mass.In order to convert from grams to formula units, you must first convert grams to moles, then moles to formula units (grams --> moles --> formula units).1. Divide the mass (g) of the given substance by the substance's molar mass.2. Multiply the number of moles found in Step 1 (above) by Avogadro's number (6.022 x 1023).---- Mass substance ----- X 6.022 x 1023 formula unitsMolar mass substanceCONVERSION FACTOR47.63g substance x 1 mol substance ---- x ----- Avogadro's number///////////////////// molar mass (g) substance ////// 1 mol substance


How many formula units in 3.6 grams of NaCl?

1 mole NaCl = 58.443g NaCl = 6.022 x 1023 formula units NaCl 3.6g NaCl x 1mol NaCl/58.443g NaCl x 6.022 x 1023 formula units NaCl/mol NaCl = 3.7 x 1022 formula units NaCl