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How many grams of ammonium sulfate (MW 132.1) are needed to make 1.5 L of an 8 M solution?
Wiki User
∙ 6y ago
Use the compbined equation
mass(g) / Mr = [conc] x vol(mL) / 1000 ( = moles)
Algebraically rearrange
mass(g) = Mr X [conc] x vol(mL)/1000
Substituting
mass(g) = 132.1 x 8Mol/L x 1500 mL/ 1000 = 1585.2 g
or 1.5852 kg
NB The '1000' is used to convert the units of L(itres) in 'M' to mL.
lenpollock
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How many grams of ammonium carbonate would you need to make 2.10 liters of a 0.619 M solution?
124,9 g grams of ammonium carbonate are needed.
What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?
The molar mass of ammonium sulfate is 132,14 g.
How many milliliters of an aqueous solution of 0.123 M cobalt(II) sulfate is needed to obtain 3.14 grams of the salt?
164,7 mL are needed.
How many milliliters of an aqueous solution of 0.149 M ammonium acetate is needed to obtain 16.9 grams of the salt?
The answer is 1 471,5 mL.
When 250. mL of a 0.15 M solution of ammonium sulfide (NH4)2S is poured into 120. mL of a 0.053 M solution of cadmium sulfate CdSO4 how many grams of a yellow precipitate of cadmium sulfide CdS are fo?
0.92g
How many grams of ammonium sulfate are needed to make a 0.25M solution at a concentration of 6M?
5.50
How many grams of ammonium sulfate are needed to make a .25 M solution at a concentration of 6M?
1.5 moles
How many grams per liter ammonium sulfate are in a saturated solution of ammonium sulfate?
744 g/L of ammonium sulphate, at 20 0C
How many grams of ammonium carbonate would you need to make 2.10 liters of a 0.619 M solution?
124,9 g grams of ammonium carbonate are needed.
What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?
The molar mass of ammonium sulfate is 132,14 g.
What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?
31.4
How many milliliters of an aqueous solution of 0.123 M cobalt(II) sulfate is needed to obtain 3.14 grams of the salt?
164,7 mL are needed.
What is the weight in grams of 1 mole of ammonium sulfate NH42 SO4?
The weight is 132.15 g.
How many milliliters of an aqueous solution of 0.149 M ammonium acetate is needed to obtain 16.9 grams of the salt?
The answer is 1 471,5 mL.
When 250. mL of a 0.15 M solution of ammonium sulfide (NH4)2S is poured into 120. mL of a 0.053 M solution of cadmium sulfate CdSO4 how many grams of a yellow precipitate of cadmium sulfide CdS are fo?
0.92g
Mass of 1.60 mol of ammonium sulfate?
you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g
If there are 20 grams of NH3 dissolved in 100 grams of water at 30 degrees C. What type of solution will you have?
This is a homogeneous solution of ammonium hydroxide in water.
