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How many grams of boron tribromide must be weighed out to get a sample of boron tribromide that contains 11.8 g of bromine?
Wiki User
∙ 14y ago
The Atomic Mass of boron is 10.811 while that of bromine is 79.904. Thus the ratio of the mass of bromine to the total mass of boron tribromide must be:
3(79.904)/[3(79.904) + 10.811] = 0.9568. The required mass of BBr3 thus is 11.8/0.9568 = 12.3 g, to the justified number of significant digits.
Wiki User
∙ 14y ago
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