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2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
Take the actual sample weight of 13grams, and divide it by the atomic weight of chromium. This gives you your molar percentage of atoms. Now multiply this molar percentage by Avogadro's constant, the number of atoms in one mole, and this will give you your number of atoms in the sample.
Not much! 2980 atoms sodium [1 mole Na/6.022 X 1023 (atoms)][22.99 grams/1 mole Na] = 1.138 X 10 -19 grams sodium ====================
86.0 grams Sn (1 mole Sn/118.7 grams)(6.022 X 1023/1 mole Sn)= 4.36 X 1023 atoms of tin=================
12.044*10^23 atoms 1.5055*10^23 S8 molecules
904,000,000,000,000,000,000,000 (9.04 X 10^23) Bromine atoms.
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
There are 57.6 grams of tin in that sample.
24,163 ng
It is 1 copper and 2 bromine but they are not grams they are atoms, it is a particle made up of 1 copper atom and 2 bromines
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
63.8g
Take the actual sample weight of 13grams, and divide it by the atomic weight of chromium. This gives you your molar percentage of atoms. Now multiply this molar percentage by Avogadro's constant, the number of atoms in one mole, and this will give you your number of atoms in the sample.
Taking Avogadro constant to be 6.022 X 1023The no. corresponds to 1 mol Br atoms = 80 g(Approx)
You can use atomic weight to calculate the number of atoms in a given sample of an element. # g of sample element x (6.02 x 1023 / atomic weight in grams) = # of atoms
1.659 [grams] / 47.998 [grams / mol] * 6.02214179(30)×1023 [molecules / mole] * 3 [atoms / molecule]. A bunch.
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.