34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca)
= 13.8 grams calcium
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2,55 moles of the compound CO have 71,4 grams.
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
1 mole Co = 58.933g Co (atomic weight in grams)1 mole Co atoms = 6.022 x 1023 atoms CoConvert grams Co to moles Co.22.6g Co x (1 mole Co/58.933g) Co = 0.383 mole CoConvert mole Co to atoms Co.0.383 mole Co x (6.022 x 1023 atoms Co/1 mole Co) = 2.31 x 1023 atoms Co
There is no compound with the formula CaCO the here is howver CaCO3 which is calcium carbonate. If the question was chemical names of Ca and CO then the answer is calcium and carbon monoxide
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
Calcium has Wt 40, carbon is 12 and oxygen 16, so the MWt of calcium carbonate is 40+12+3x16=100. As this contains 40 calcium, calcium carbonate is 40% calcium. 40% of 418 is 167.2grams
13.2g
2,55 moles of the compound CO have 71,4 grams.
3.69 grams CO (1mol CO/28.01g CO )(6.022 X 10^23/1mol CO ) = 7.93 X 10^22 molecules
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
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160...cant quite grasp HOW though
0.87 g
The answer is 445,6 g carbon dioxide.
26,3 g cobalt is equivalent to 0,446 moles.
5.34 grams W(CO)6 (1 mole W(CO)6/351.86 grams)(6 moles C/1 mole W(CO)6)(6.022 X 1023/1 mole C) = 5.48 X 1022 atoms of carbon ========================
1 mole Co = 58.933g Co (atomic weight in grams)1 mole Co atoms = 6.022 x 1023 atoms CoConvert grams Co to moles Co.22.6g Co x (1 mole Co/58.933g) Co = 0.383 mole CoConvert mole Co to atoms Co.0.383 mole Co x (6.022 x 1023 atoms Co/1 mole Co) = 2.31 x 1023 atoms Co