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3 grams
To completely react with 0.65 g of H2 to produce HCl we need 23.08 g chlorine.
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
75,10 g of chlorine = 2,1183 moles
They use a number called a mole. This many atoms of an element equals its atomic weight in the periodic table. Molecular weight is the sum of atomic weight. Silver has an atomic weight of 108 grams/mole and Chlorine is 35.4 grams/mole. This makes AgCl 108 + 35.4 = 143.4 grams/mole. The % Chlorine is the atomic weight of Chlorine divided by the molecular weight of AgCl. 1 mole of AgCl would contain 35.4 grams / 143.4 grams = 25% Chlorine by weight. 1.22 grams AgCl would contain (0.25)*(1.22) = 0.30 grams of Cl. To find the Chlorine in the unknown, divide the weight of Chlorine from the experiment by the initial weight of the unknown. 0.30 grams / 0.63 grams = 0.48 = 48% Cl by weight.
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3 grams
To completely react with 0.65 g of H2 to produce HCl we need 23.08 g chlorine.
This question can not be answered, not even by your teacher: not enough correct information." How many grams (of WHAT ?) would 29.48 L of chlorine gas produce (after doing WHAT ?) "
How many grams does NO from periodic table have
Multiply the moles given, by the atomic mass of chlorine and you have your answer. (3.55 Grams)
Balanced equation. H2 + Cl2 >> 2HCl 146 grams HCl (1mol/36.458g)(1mol Cl2/2mol HCl)(70.9g/11mol Cl2) = 72.9 grams
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
75 g sodium chloride contain 29,75 g sodium.
none
75,10 g of chlorine = 2,1183 moles
They use a number called a mole. This many atoms of an element equals its atomic weight in the periodic table. Molecular weight is the sum of atomic weight. Silver has an atomic weight of 108 grams/mole and Chlorine is 35.4 grams/mole. This makes AgCl 108 + 35.4 = 143.4 grams/mole. The % Chlorine is the atomic weight of Chlorine divided by the molecular weight of AgCl. 1 mole of AgCl would contain 35.4 grams / 143.4 grams = 25% Chlorine by weight. 1.22 grams AgCl would contain (0.25)*(1.22) = 0.30 grams of Cl. To find the Chlorine in the unknown, divide the weight of Chlorine from the experiment by the initial weight of the unknown. 0.30 grams / 0.63 grams = 0.48 = 48% Cl by weight.