The mass is 80 g iron)III) oxide.
One. because Iron (II) Oxide -----> FeO. so that's 1 iron for ever oxygen. So yeah just one. Unless your asking how many molecules? That would mean it's 6.02x10^23 since that's avagadro's number multiplied by the number of moles, which in this case is just 1.
Assuming "rust" to be Fe2O3 rather than a lesser predictable mix of various compounds... 2 moles Fe per 1 mole rust = 2.4/2 = 1.2mols rust. 3 moles O per 1 mole rust = 1.2 x 3 = 3.6 mols O. However...it may be noted that oxygen naturally exists as a diatomic molecule and so it should be explicitly stated whether the amount of monatomic or diatomic oxygen is wanted. 3.6 mols O ...or... 1.8 mols O2
Depend on it's valence state. Iron is transition metal and had many possible valence state (e.g. Fe2+ or Fe3+). For the case Fe2+ then it is just FeO and 1 atom informula but if it is Fe3+ then it is Fe2O3 and thus 2 atoms. You must check what written clearly, for iron oxide such as rust, it is wrtten as iron(III)oxide to stand for being a Fe3+.
iron(II) oxide is FeO and has two ions Fe2+ and O2-
1.8 mol
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
four moles. Approximately. Oxygen has a molecular weight of 16.0 grams per mole so 64 grams divided by 16.0 grams per mole is four moles.
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
25 moles of sulfur dioxidecontain 800,825 g oxygen.
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
16 grams of oxygen how many moles is 0,5 moles.
999 g
320 grams of oxygen is the equivalent of 10 moles.
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
12.8 grams oxygen (1 mole O/16.0 grams) = 0.800 moles of oxygen
C + O2 = CO2 So the theoretical number of moles are 1 each. number of moles is mass/molecular weight C = 6/12 which is 0.5 O2 = 11/32 which is 0.34375 Oxygen is the limiting reagent. So 0.34375 moles is reacted and this also gives 0.34375 moles CO2 no moles is mass over molecular mass grams is moles x molec mass 0.34375 x 44 = 15.125 grams CO2 formed. learn the technique. this is needed in science
2Mg + O2 -> 2MgO1 mole of Oxygen yields two moles of MgOmoles of oxygen = 0.643 molmoles of MgO formed = 1.286 molgrams of MgO formed = 40.3 X 1.286 = 51.8258 g
49.7g O2
0,667 g oxygen equal 0,021 moles.
The answer is 224,141 grams oxygen.
four moles. Approximately. Oxygen has a molecular weight of 16.0 grams per mole so 64 grams divided by 16.0 grams per mole is four moles.
0,800 moles of oxygen (O2) is equivalent to 25,6 g.