Sulfur dioxide is SO2, so there are 2 moles of oxygen for each mole of sulfur. In 25 moles of SO2, there are 25 moles of S, so there must be 50 moles of oxygen, or 25 moles of diatomic oxygen gas (O2).
Assuming the two reactants are producing sulfuric acid according to the balanced equation H2S + 2O2 --> H2SO4:
2.5g H2S = 0.07mol H2S = 0.14mol O2. 0.14mol x 32g/mol (for O2) = 4.48g O2.
We need 800 g oxygen
4.08
769.0 grams
You would need 18 grams to get the requirement. Using a chemical equation can help to solve this for you.
2
0.125 mole
42 J
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
16.0 g
15.0
800 g oxygen are needed.
17.9 grams
When you resubmit your question please indicate which gas is of interest to you.
75 grams water is equal to 4,166 moles.
13.8 g
28g Fe
How many grams of oxygen are needed to react completely with 200.0 g of ammonia, NH3?4NH3(g) + 5O2(g) => 4NO(g) + 6H2O(g)
You need 150,41 g oxygen.