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Energy is actually given off in the lowering of temperature. Use the equation Q = mc(change in T). In this case, m = 2.9, c = 4.179 J, and change in T = -12.1 degree C. Now solve for Q, the heat energy. This exothermic process gives off approximately 146.6 J of heat.

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9y ago
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13y ago

q(Joules) = mass * specific heat * change in temperature

q = 53.5 grams H2O * 4.180 J/gC * (70.1 C - 16.5 C)

= 11987 Joules

Only 3 significant figures should be used given the numbers in your question. The answer would be correctly written as: 1.20 kJ

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11y ago

q = m x C x (Tf - Ti)

q = amount of heat energy gained or lost by substance m = mass of sample in grams = 2.83kg = 2830g C = heat capacity (J/ g•oC) = 4.18J/ g•oC

Tf = final temperature = 46 oC

Ti = initial temperature = 38 oC

(Tf - Ti) = 46 oC - 38 oC = 8 oC

q = 2830g x 4.18J/ g•oC x 8 oC = 9.46 x 104 J

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9y ago

The number of joules to raise one gram of water by one degree Celsius is 4.2 Joules. The total number of joules needed then is 95,088 joules.

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9y ago

It takes 4.2 joules per gram of water to raise the temperature by one degree Celsius. The total number of joules is then 190.176 kilojoules.

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10y ago

46 calories (or 192,464 joules) for each Celsius degree.

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12y ago

q(Joules) = mass * specific heat * change in temperature

q = (20 grams H2O)(4.180 J/gC)(40o C - 30o C)

= 836 Joules needed

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15y ago

0.0796636 J

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Q: How many joules are necessary to raise the temperature of 53.5 grams of water from 16.5 degrees celsius to 70.1 degrees celsius?
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