Strictly, elements such as calcium do not have "moles", but the corresponding term, for Avogadro's Number of atoms of an element, is called "gram Atomic Mass". For calcium, this number is about 40.08 grams. Therefore, 9.8 grams of calcium is about 9.8/40.08 or 0.24 gram atoms, to the justified number of significant digits.
if my calculations are correct it should be 9g (mass) divided by 18 (RFM of H2O) = 0.5
You first need to know what element, or the molecular formula of the 9.8 grams consists of.
The molar mass of calcium is 40 g/mol. Therefore, 9.8 g of calcium is equivalent to 0.245 moles.
Molar mass of water:-18g
=> 18g contains 6.022*1023 molecules
=> 9g contains 6.022*1023 /2=3.011 *1023 molecules
18 moles of atomic hydrogen or 9 moles of molecular hydrogen is needed.
9,8 moles of calcium have 392,76 grams.
.391 moles of Na in NaCL
90/18 = 5 moles
1/2 mol
The weight of 2,5 mol of sulfuric acid is 245,1975 g.
The mol mass of sulfuric acid is 98.078 g/mol, 98 g of sulfuric acid therefore contains 0.9992 moles. Using consistent significant figures and your calculations, 98 g sulfuric acid would be equal to 1.0 mol sulfuric acid.
H2SO4 H= 1X2 = 2 S=32X1=32 O=16X4=64 TOTAL: 98 98x3= 294 GRAMS =))
About 0.2161 pounds to 98g
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
2 moles H2SO4 (98.086 grams/1 mole H2SO4)= 196.172 grams of sulfuric acid====================
The weight of 2,5 mol of sulfuric acid is 245,1975 g.
98 pounds is 44,452.1 grams.
There are .098 liters in 98 grams of ethanol.
The mol mass of sulfuric acid is 98.078 g/mol, 98 g of sulfuric acid therefore contains 0.9992 moles. Using consistent significant figures and your calculations, 98 g sulfuric acid would be equal to 1.0 mol sulfuric acid.
H2SO4 H= 1X2 = 2 S=32X1=32 O=16X4=64 TOTAL: 98 98x3= 294 GRAMS =))
98 kg = 98000 g
About 0.2161 pounds to 98g
No such thing as HSO in chemistry. If you're referring to H2SO4, which is sulfuric acid, then 125 grams of it would be: H2SO4 = 98g/mol; 98/1=125/x; solve for x to get about 1.28 moles.
There are 1000 milligrams in a gram. You have to divide by 1000. 98/1000 is 0.098g
Sulfuric acid has a molecualr weight of 98 and so 2.5 moles would weigh 245 g
98 g = 0.098 kgTo convert from g to kg, divide by 1000.