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16,8 L of Xe gas at STP is equivalent to 0,754 moles.
To determine how many atoms are present in 56 liters of oxygen gas at STP you first need to know that there are two atoms in a single molecule. Then, you would work the scientific formula to determine the number of molecules in the oxygen gas.
One mole has amass of 16g.There are 6.428mol.Its mass is 102.85g
At STP, one mole of any gas occupies 22.4 liters. This is called molar volume. 113.97 liters ÷ (22.4 L/mol) = 5.09 moles Then convert moles to molecules (1 mole = 6.02 × 1023 molecules) 5.09 moles × (6.02 × 1023 molecules/mol) = 3.06 × 1024 molecules
Assuming that this ammonia gas is at STP, you can use Avogadro's number to gind the number of moles of gas:(387 x 1021 molecules) x (1 mol / 6.02x1023particles) x (17.03 g / 1 mol) =110 g NH3
How many molecules are in 30 liters of methane (CH4) at STP
The volume is 19,48 L.
The answer is 8,5379.10e23 molecules.
16,8 L of Xe gas at STP is equivalent to 0,754 moles.
To determine how many atoms are present in 56 liters of oxygen gas at STP you first need to know that there are two atoms in a single molecule. Then, you would work the scientific formula to determine the number of molecules in the oxygen gas.
1.12 X10 to the 23rd power molecules SO2
6.023 x 1023
If its at STP (standard temperature & pressure) then i think 6 x 10^23 molecules
atoms have a higher mass than molecules. Because both gases at STP have the same number of molecules per unit volume, the gas must be denser.
at STP 1 mole occupies 22.4 litres. 64.28 / 22.4 is 2.8696428 moles. Multiply this by avagadro's constant (6.022*10^23) gives 1.7281x10^24 molecules
A cubic decimeter is a liter, so we're talking 50L of oxygen gas at STP. 1mol of any gas at STP occupies 22.4L of space, so 50/22.4 = about 2.2mol of oxygen.
at stp 1 mole of a gas contains 22.4 litres. 9.1/22.4= .40625 moles o2. 1 mole of a gas contains 6.022E23 molecules so .40625 moles x 6.022E23 = 2.4464325E23 molecules, but you have to multiply by two due to it being diatomic, so answer x 2 = 4.892875E23 molecules