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2.41X1023 Molecules

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Q: How many molecules are in 0.400 mol N2O5?
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How many molecules are present in 1296 g of dinitrogen pentoxide (N2O5)?

1296 g N2O5 x 1 mol N2O5/108 g x 6.02x10^23 molecules/mole = 7.22x10^24 molecules


how many moles of NO2 are in 7.4 mol N2O5?

N2O5(g) → 4NO2(g) + O2(g)


How many molecules are present in 1296 g of dinitrogen pentoxide?

Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.


How many Molecules are contained in 0.900 mol O2?

5.418E23 molecules


How many molecules are there in 1.00 mol of H2O2?

There are 6.022x10^23 molecules in 1.00 mol of anything.


How many molecules are in 2 mol of tryptophan?

The answer is 12,046.1023 molecules.


How many carbon tetrachloride molecules are in 3.54 mol carbon tetrachloride CCl4?

3.54 (mol) * 6.02*1023 (molecules/mol) = 2.13*1024molecules (of any substance)


How many molar mass in g mol of dinitrogen pentoxide?

N2O5 Has a molar mass of 108.01 g/mol 1.73 mol x 108.01 g/mol = 187 grams


How much would two moles of dinitrogen pentoxide weigh?

The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g


How many molecules are contained in 1.20 mol O2?

The number of molecules is 7,2265690284.10e23.


How many molecules of sulfur tetrafluoride are present in 2.13 moles of this compound?

There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.


How many molecules are in 6.30 mol CO2?

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