2.41X1023 Molecules
The answer is 12,046.1023 molecules.
3.54 (mol) * 6.02*1023 (molecules/mol) = 2.13*1024molecules (of any substance)
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
6.022 * 10^21
1 mole of molecules = 6.022 x 1023 molecules 0.536mol x 6.022 x 1023 molecules/mol = 3.28 x 1023 molecules
1296 g N2O5 x 1 mol N2O5/108 g x 6.02x10^23 molecules/mole = 7.22x10^24 molecules
N2O5(g) → 4NO2(g) + O2(g)
Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.
5.418E23 molecules
There are 6.022x10^23 molecules in 1.00 mol of anything.
The answer is 12,046.1023 molecules.
3.54 (mol) * 6.02*1023 (molecules/mol) = 2.13*1024molecules (of any substance)
N2O5 Has a molar mass of 108.01 g/mol 1.73 mol x 108.01 g/mol = 187 grams
The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g
The number of molecules is 7,2265690284.10e23.
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
my Glizzy