Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
C2H4 + 3 O2 --> 2 CO2 + 2 H2OSo 2.16 mol O2 will produce 1.44 mol H2O(and 1.44 mol CO2)because 3:2 = 2.16 : 1.44
The molar volume at 1 bar and 0 0C is 22,710 980(38) L/mol; each mol contain 6,022 140 857.10e23 molecules.
The answer is 12,046.1023 molecules.
2.41X1023 Molecules
my Glizzy
2.65 mol * 64.07 g/mol = 169.79 g
1 mol = 6.02 * 10^23 molecules 0.018 mol = 6.02 * 10^28 * 0.018 molecules 1.0836 * 10^27 molecules of CO2
1 mol = 6.02 * 10^23 molecules 0.018 mol = 6.02 * 10^28 * 0.018 molecules 1.0836 * 10^27 molecules of CO2
Avagadro's number says there are 6.02x1023 particles of a pure substance in one mole of that pure substance. (A particle is an atom, molecule, or ion.)(2.1 mol CO2) (6.02x1023 molecules CO2/1 mol CO2)= (2.1)( 6.02x1023 molecules CO2) = 1.26 x 1024 molecules CO2
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
C2H4 + 3 O2 --> 2 CO2 + 2 H2OSo 2.16 mol O2 will produce 1.44 mol H2O(and 1.44 mol CO2)because 3:2 = 2.16 : 1.44
5.418E23 molecules
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
(90 g CO2 / (12.0+2*16.0) g/mol CO2) = 2.05 mol CO2 = 2.05 mol C2.05 mol C * 12.0 g/mol C = 24.5 g C
There are 6.022x10^23 molecules in 1.00 mol of anything.
The molar volume at 1 bar and 0 0C is 22,710 980(38) L/mol; each mol contain 6,022 140 857.10e23 molecules.