26.3 g of calcium hydroxide contain 2,054 molecules.
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
The answer is 1,57.10e27 molecules.
1,4.10e23 molecules
The answer is 1,357.10 ex.23 molecules.
n = gmol = N molecules / N Avogadro n = ( 2.4 x 10^23 molecules ) / ( 6.022 x 10^23 molecules per gmol ) n = 0.3985 gmol m = ( n ) ( M ) m = ( 0.3985 ) ( 141.94 g per gmol ) = 56.6 g <----------------------
The number of ammonia molecules is 5,83.10e19.
22.0 g of silver chloride contain 0,918.10e23 molecules.
26.3 g of calcium hydroxide contain 2,054 molecules.
334 g x 1 mol/331.6 g x 6.02x10^23 molecules/mole = answer
325 g of CBr4 have 5,9.10e23 molecules.
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
Mass(g)of N = 35.8 g NH4NO3 X 28 g of N / 80 g NH4NO3 = 12.53 g N
ng = n*g so there are n gs in ng
The answer is 8,5379.10e23 molecules.
The number of molecules is 6,3985.10e24.
2.05×1022 molecules