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Q: How many molecules of Br2 are present in 5 moles of Br2?
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How many particles are in 9.00 moles of Br2?

9 moles of bromine contain 54,2.10e23 molecules.


How do you calculate the number of moles of bromine present in 16.0ml of Br2 whose density is 3.12gml?

First convert the volume of the Br2 into grams by using:D=M/VSo we are given that volume=16.0 ml and density=3.12g/ml.M=D*VM=(3.12g/ml)*(16.0ml)=49.92 gThen we use #moles of a substance=#grams present/Formula weight(# of grams of Br2 in 1 mol of Br2)The Formula weight(molar mass) of Br2=2*(79.9 g/mol)=159.80 g/mol Br2#moles of Br2=49.92g/159.80g/mol Br2=.312 moles of Br2 present.


How many atoms are in 1.54 moles of Bromine Br?

If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.


How many moles are there in 160g of bromine molecules?

Amount of Br2 = mass of sample / molar mass = 160 / 2(79.9) = 1.00mol


How many moles of atoms are in 44.0 Br2?

44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms


What is the mass of 4.89 x 1020 molecules of Br2?

1 mole Br2 = 159.808g Br2 = 6.022 x 1023 molecules Br2 4.89 x 1020 molecules Br2 x 1mol Br2/6.022 x 1023 molecules Br2 x 159.808g Br2/mol Br2 = 0.130g Br2


How many moles are contained in 44.0 g Br2?

0.275


How many grams are in 2.9 moles of Br2?

2,9 moles of bromine is equivalent to 463,4432 g.


How many moles of Br2 are there in 160g?

1,012 mole of bromine for the diatomic molecule.


How many moles of bromine will be formed upon the complete reaction of 0.248 moles bromine trifluoride?

The complete decomposition reaction is as follows:2 BrF3 → Br2 + 3 F2 , so 2 moles BrF3 will give 1 mole Br2 , hence 0.248 mole gives 0.124 mole Br2


How many atoms of bromine will you multiply to get moles of bromine?

One mole of Br2 has 6.023 x 1023 bromine molecules or 2 x 6.023 x 1023 bromine atoms.


How many atoms are in 1.54 moles of Bromine?

1.54 (mol Br2) * 6.022*10+23 (molecule/mol Br2) * 2 (atoms Br/molecule Br2) =1.85*1024 atoms in 1.54 mole Br2