http://en.wikipedia.org/wiki/Chlorine 1 mol of chlorine (Cl2) weighs (2*35.45 =)70,90 grams 134,5 grams of chlorine is (134,5/70,9 =) 1,897 mol of chlorinegas. 1,897 * 6,02 * 10^23 = 1,142 * 10^24 molecules of Cl2
Multiply the moles given, by the atomic mass of chlorine and you have your answer. (3.55 Grams)
70
384.5g
3
Chlorine gas is Cl2If you have 4.37 x 1018 atoms, you will have half that number of chlorine molecules.4.37 x 1018 atoms of Cl x 0.5 molecules of Cl2 / atoms of Cl = 2.20 x 1018 molecules of Cl2There are 6.02 x 1023 'things' in a mole.2.20 x 1018 molecules of Cl ÷ 6.02 x 1023 molecules / mole = 3.65 x 10-6 mole of Cl2.
1000 g = 1 kg ⇒ 1345 g = 1345 ÷ 1000 kg = 1.345 kg
64 moles of chlorine atoms would be 64 x 35.5 grams, i.e. 2272 grams. If you meant the substance chlorine, which consists of Cl2 molecules, it would be 4544 grams.
1345
Chlorine gas (at standard temperature and pressure) consists of diatomic molecules. Therefore, in the specified number of molecules of chlorine gas there are 1.364 X 1025 atoms. The gram atomic mass of chlorine, which by definition consists of Avogadro's Number of atoms, is 35.453. Therefore, the mass of the specified number of molecules of chlorine gas is 35.453 X [(1.364 X 1025)/(6.022 X 1023)] or 803 grams, to the justified number of significant digits.
Since 35.5 is the approximate atomic mass of chlorine and each molecule contains two atoms of chlorine, the number of molecules is about half of Avogadro's Number, 3.01 X 1023.
Multiply the moles given, by the atomic mass of chlorine and you have your answer. (3.55 Grams)
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
75 g sodium chloride contain 29,75 g sodium.
none
75,10 g of chlorine = 2,1183 moles
25 grams / (17 grams/mole) x 6.022x1023 molecules/mole = 8.9x1023 molecules
there are 6 molecules of chlorine gas