The molecular weight of sodium (Na) is 22.99 grams. The molecular weight of chlorine (Cl) is 35.45 grams. Therefore, there are 58.44 grams in 1 mole of NaCl. So, in 3.25 moles of NaCl, there are 58.44 gr x 3.25 = 189.93 grams.
Every mol of NaCl contains a mol of Na, weighting 23 grams, and a mol of Cl, weighing 35.5 grams. So, every mol of NaCl weights 58,5 (=23+35.5) grams. Therefore, 145 moles of NaCl weights 8482.5 grams.
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl
how many moles are in 5.6 grams of Na?
1 mole NaCl = 58.442g NaCl (the atomic weight of Na and Cl in grams) 13g NaCl x (1mol NaCl/58.442g NaCl) = 0.22mol NaCl
Molarity = moles of solute/Liters of solution Find moles NaCl 9 grams NaCl (1 mole NaCl/58.44 grams) = 0.154 moles NaCl Molarity = 0.154 moles NaCl/1 Liter = 0.2 M sodium chloride -------------------------------
(7.6 g NaCl) (moles NaCl/58.44 g NaCl) (1 mole Na/1 mole NaCl) ( 22.99 g Na/mole Na) = 2.989 g Na or 3.0 g Na (significant figures) Steps: 1. Change everything to moles: use molar mass/molecular of NaCl 2. Find the molar ratio: since there are 1 Na in every NaCl, then the ratio of NaCl to Na is 1:1 3. Change moles back to grams: use the molar mass/molecular weight of Na 4. Watch out for significant figures! I hope this is right
1 mol of NaCl is 58.5 grams (Ar of Na is 23, and Ar of Cl is 35.5). Now we set up an equation1 mol : x = 58.5 g : 2.4 gx = 0.0410 molSo, 2.4 grams of NaCl has 0.0410 moles of NaCl.?
Molar Mass NaCl is 58.5g, 39.3% Na (5.90g), Molar Mass Na is 23.0g, 5.90/23.0 = 0.256 moles
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
For this conversion you need the atomic masses of the two elements to find the molecular mass of the NaCl.Na: 23.0Cl: 35.5NaCl: 58.5Then, you follow the formula:Mass in grams Ã· Molecular mass = Mass in moles1000 g NaCl Ã· 58.5 = 17.1 moles NaCl
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
The answer is 0,25 moles.
2 * [(Na=23) + (Cl=35.5)] = 117 grams NaCl
The atomic weight of Na is 23.0 g/molTo convert moles to grams:grams Na = 2.04 mol Na23.0 g = 46.9 g Na1 molMultiply by grams per mole. Moles cancel out.
In each formula unit of NaCl there is one Na+ ion. Therefore, amount of sodium ions = amount of NaCl = 4.25mol
First, find the moles of NaCl. Because you have 400 milligrams of NaCl convert to grams by dividing 1000mg. 400mg/1000mg = 0.400 grams of NaCl. Now we need to convert to moles. For every mole of NaCl there is 58.44 grams. (22.99g Na + 35.45 g Cl) so using stoichiometry (grams cancel) I get .0068 moles of NaCl. Conver 100 mL to L by dividing by 1000mL. Therefore there is .001 L in the solution. Molarity is moles per Liter. So 0.0068 mols of NaCl / 0.001 L = 6.84 M
I'm going to assume that you mean 23.34g of NaCl. 1 mole NaCl = 58.442g NaCl (the atomic weight of Na and Cl in grams) 23.34g NaCl x (1mol NaCl/58.442g NaCl) = 0.3994mol NaCl
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.11.5 grams Na / (23.0 grams) = .500 moles Na
1 mole of NaCl: Na = 1 * 22.99 g = 22.99 g Cl = 1* 35.45 g = 35.45 g Total = 58.44 g 238 g NaCl * (1 mol NaCl/58.44 g NaCl) = 4.07 mol NaCl There are approximately 4.1 moles in 238 grams of sodium chloride.
3 moles Na2CO3 (2moles Na/1mole Na2CO3)(22.99 grams Na/1 mole Na) = 138 grams of sodium
There are 5 formula masses of Na in 5 formula masses of NaCl, as indicated by the fact that the symbol for sodium has no explicit subscript in the formula of NaCl. Neither sodium nor sodium chloride has moles in the strictest sense, since neither of them is covalently bonded.
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.17.5 grams Na / (23.0 grams) = .761 moles Na
Molar mass of Na = 22.9898g/mol Molar mass of Cl = 35.45g/mol Total molar mass = 58.4398g/mol 58.4398g * 3.7mol =216.22726g