15.8 grams of C6H12O6 is equivalent to 0.087 moles.
671
Moles = mass in grams / atomic weight So moles in 15.01 g of Ar = 15.01 / 39.948 = 0.38 moles
How many moles of atoms are contained in 382 g Co
74.3 g Na2CrO4 x 1 mole/162 g = 0.459 moles (3 sig figs)
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
671
Moles = mass in grams / atomic weight So moles in 15.01 g of Ar = 15.01 / 39.948 = 0.38 moles
0,27 moles of calcium contain 10,82 g calcium.
35.0 moles nitrogen (1 mole N/14.01 grams) = 2.50 moles nitrogen ----------------------------
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
# moles = mass / molar mass = 1.23g / 83.80g/mol =1.47x10^-2 moles There are 1.47x10^-2 moles in 1.23g of krypton
0.67 moles of C6H12O6
Formula mass of MgCl2 = 24.3+2(35.5) = 95.3Amount of MgCl2 = 444/95.3 = 4.66mol4.66 moles of MgCl2 are contained within a 444g pure sample.
How many moles of atoms are contained in 382 g Co
16 grams of oxygen how many moles is 0,5 moles.
74.3 g Na2CrO4 x 1 mole/162 g = 0.459 moles (3 sig figs)