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1 g of ammonia (NH3) is equal to 0,059 mol.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
Here is the solution,for 1mole NH3 or ammonia,N: 14.0067 g/mol x 1H: 1.00794 g/mol x 3So approximately it is--> 17.03052 g/mol)Now multiply this into 4.5 for 4.5 moles of ammonia, --> 4.5x17.03052 =76.64g
0,044 moles of NH3 can be produced.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
1 g of ammonia (NH3) is equal to 0,059 mol.
The molecular formula of ammonia is NH3The molecular mass of NH3 is 14.0 + 3(1.0) = 17.0 Amount of NH3 present = mass of sample/molar mass = 100/17.0 = 5.88g
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
2N + 3H2 -> 2NH3 18 moles H2 (2 moles NH3/3 moles H2) = 12 mole ammonia
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
NH3 is balanced at 1:3, so in 3 moles NH3 there are 3*3 = 9 moles H atoms
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.
Ammonia is NH3 (not NH2) so its molar mass is 17 g/mol. In 1.2*10^3 g there are1.2*10^3(g) / 17 (g/mol) = (70.6 =) 71 mol NH3.
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
The mass of ammonia will be 95,03 g.