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How many moles are present in 480g of anhydrous magnesium sulfate?
Wiki User
∙ 9y ago
First we calculate the formula mass of the compound magnesium sulfate.Formula mass of MgSO4 = 24.3 + 32.1 + 4(16.0) = 120.4
Amount of MgSO4 in a 480g pure sample = 480/120.4 = 3.99mol
There is approximately 4 moles of the compound present in a 480g sample.
Wiki User
∙ 9y ago
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