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For this you need the atomic (molecular) mass of C3H4. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. C3H4=40.0 grams

10.0 grams C3H4 / 40.0 grams = .250 moles C3H4

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15y ago
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13y ago

10 grams C3H4 (1 mole C3H4/40.062 grams)(6.022 X 10^23/1 mole C3H4)

= 1.5 X 10^23 molecules

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8y ago

1o g ethanol is equivalent to 0,217 mol.

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10y ago

6.02 x 1024 molecules

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7y ago

8 grams of C3H4 contain 0,2 moles.

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7y ago

10 g x 1 mol/40 g = 0.25 moles

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13y ago

0.167 mol

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