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How many moles are present in 1g of H2So4?
To determine the number of moles in 1g of H2SO4, you first need to calculate the molar mass of H2SO4. The molar mass of H2SO4 is approximately 98.08 g/mol. Therefore, 1g of H2SO4 is equal to 0.0102 moles (1g / 98.08 g/mol).
How many molecusles are contained in 55.0 g of H2SO4?
how many molecules are containd in 55.0g of H2SO4
What Is the mass in grams of 6.25 moles of h2so4?
To calculate the mass of a substance in grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of H2SO4 (sulfuric acid) is approximately 98.08 g/mol. Therefore, the mass of 6.25 moles of H2SO4 would be 6.25 moles x 98.08 g/mol = 613 grams.
How many moles are in 0.50 of H2SO4?
Did you mean 0.5 g? or mg? or ml?Anyway, amount of substance in moles is calculated as m/Mwhere m is mass and M is molal mass.M (H2SO4) is 1*2 + 32 + 16*4 = 98 g/mole
What is the mass in grams of 3.60 moles of H2SO4?
To find the mass of 3.60 moles of H2SO4, you first need to calculate the molar mass of H2SO4. The molar mass of H2SO4 is 98.08 g/mol. Multiply the molar mass by the number of moles to get the mass: 3.60 moles * 98.08 g/mol = 353.088 grams. Therefore, the mass of 3.60 moles of H2SO4 is 353.088 grams.
How many moles are there in 22.4 g of H2SO4?
To find the number of moles in 22.4 g of H2SO4, you need to first calculate the molar mass of H2SO4, which is 98.08 g/mol. Then you can use the formula: moles = mass/molar mass. So, moles = 22.4 g / 98.08 g/mol, which equals 0.228 moles of H2SO4.
How many moles are present in 1g of H2So4?
To determine the number of moles in 1g of H2SO4, you first need to calculate the molar mass of H2SO4. The molar mass of H2SO4 is approximately 98.08 g/mol. Therefore, 1g of H2SO4 is equal to 0.0102 moles (1g / 98.08 g/mol).
How many molecusles are contained in 55.0 g of H2SO4?
how many molecules are containd in 55.0g of H2SO4
What Is the mass in grams of 6.25 moles of h2so4?
To calculate the mass of a substance in grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of H2SO4 (sulfuric acid) is approximately 98.08 g/mol. Therefore, the mass of 6.25 moles of H2SO4 would be 6.25 moles x 98.08 g/mol = 613 grams.
How many moles are in 0.50 of H2SO4?
Did you mean 0.5 g? or mg? or ml?Anyway, amount of substance in moles is calculated as m/Mwhere m is mass and M is molal mass.M (H2SO4) is 1*2 + 32 + 16*4 = 98 g/mole
What is the mass in grams of 3.60 moles of H2SO4?
To find the mass of 3.60 moles of H2SO4, you first need to calculate the molar mass of H2SO4. The molar mass of H2SO4 is 98.08 g/mol. Multiply the molar mass by the number of moles to get the mass: 3.60 moles * 98.08 g/mol = 353.088 grams. Therefore, the mass of 3.60 moles of H2SO4 is 353.088 grams.
How many milliliters of 3.0 m h2so4 are required to react with 0.80 g of cuo in the equation cuo h2so4 cuso4 H2O?
We need to go from grams of CuO to mL of H2SO4. Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO (.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel) Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4 3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4 (0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel) So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.
What is 0.736 moles H2SO4 into grams?
To convert moles to grams, you need to use the molar mass of the compound. The molar mass of H2SO4 is 98.08 g/mol. Therefore, 0.736 moles of H2SO4 is equal to 0.736 * 98.08 = 72.16 grams.
What mass of H2SO4is contained in 60.00 mL of a 5.85 M solution of sulfuric acid?
To calculate the mass of H2SO4, you first find the moles of H2SO4 using the molarity formula (moles = molarity x volume). Then use the molar mass of H2SO4 (98.08 g/mol) to convert moles to grams. Given that the solution is 5.85 M, you would first calculate moles of H2SO4: 5.85 mol/L x 0.060 L = 0.351 mol. Then convert moles to grams: 0.351 mol x 98.08 g/mol ≈ 34.44 grams of H2SO4.
What mass of h2so4 would required to prepare 750 ml of a 0.15m h2so4 solution?
To calculate the mass of H2SO4 required, first calculate the number of moles needed using the formula: moles = molarity x volume (in liters). Then, multiply the moles by the molar mass of H2SO4 (98.08 g/mol) to find the mass. moles = 0.15 mol/L x 0.75 L = 0.1125 mol mass = 0.1125 mol x 98.08 g/mol ≈ 11.04 g of H2SO4.
How many moles are present 392g of H2So4?
196 grams H2SO4 (1 mole H2SO4/98.096 grams)(6.022 X 10^23/1 mole H2SO4) = 1.20 X 10^24 molecules of sulfuric acid
How many grams are in 0.50 mol H2SO4?
The weight of 2,5 mol of sulfuric acid is 245,1975 g.
