0
This depends on the chosen concentration !
Wiki User
∙ 9y ago
Add your answer:
Earn +20 pts
What is the mole concentration of 58.44g of NaCl in 1 L of water?
Molarity = moles of solute/Liters of solutionGet moles NaCl.58.44 grams NaCl (1 mole NaCl/58.44 grams)= 1 mole NaCl------------------Molarity = 1 mole NaCl/1 liter= 1 M NaCl========
How many moles of sodium chloride are in 5.08 L of a 2.36 M solution?
Molarity = moles of solute/Liters of solution ( find the moles ) 2.36 M NaCl = moles NaCl/5.08 Liters NaCl = 12.0 moles
What is the molarity of a 2.000 L solution thatis made from 14.60 g of NaCL?
Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------
How much of NaCl is in 1.84 L of 0.200 M NaCl Answer in units of mol.?
(1.84 L)(0.200 mol/L) = 0.368 moles NaCl
How do you find the total mass of NaCl in a 455000L pool at a constant concentration of 0.048 M?
You start by checking how many moles of NaCl you have in your pool. Number of moles=concentration*volume =0.048mole/L*455000L=21840moles Then you get the molar mass of NaCl which is 58.443 g/moles, then you multiply it by your number of moles. 21840 moles*58.443g=1'276'395g=1'276.395kg of NaCl
How many moles per mL of the solute are contained in the 0.20 M NaCl?
0.0002 mol NaCl/mLmolarity = (moles solute)/(L of solution)0.20 M NaCl = 0.20 mol NaCl/L1 L = 1000 mL0.20 mole NaCl/1000 mL = 0.00020 mol NaCl/mL (rounded to two significant figures)
How many grams of NaCl are in 1.92 moles of NaCl?
Every mol of NaCl contains a mol of Na, weighting 23 grams, and a mol of Cl, weighing 35.5 grams. So, every mol of NaCl weights 58,5 (=23+35.5) grams. Therefore, 145 moles of NaCl weights 8482.5 grams.
Why is 0.9 NaCl osmolarity 300 mOsmL calculations?
- 0,9 g/L NaCl equal to 0,154 moles - but because NaCl is dissociated in two ions in water the relation is 1 mol NaCl equal 2 osmol/L - and so 0,9 % NaCl equal 308 milliosmole/L
How many liters of chlorine 2 are needed to produce 23.002 moles of NaCl?
The volume is 254,82 L.
How to calculate the percentage of NaCl to M and mOsm?
9 g/L NaCl = 0,9 g/100 mL = 0,154 moles/L = 300 mOsm/L
What is the molarity of a solution consisting of 0.250 mol NaCl dissolved in 2.25 L of solution?
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
How do solutions dilute?
Solutions get diluted whenever there is an increase on volume but the number of moles of your substance remains the same. Eg: if I have 1 mole of NaCl in 1000ml, then I add 1000ml of water, then net volume is 2000ml but the number of moles of NaCl present is still 1 so the conc went from 1 mol/L to 0.5 mol/L. It was diluted!
