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How many moles of CH3COOH are in 458.77 g of CH3COOH?
Gp7821826810813
Remember the equation
moles = mass(g) / Mr
The Mr ( Relative molecular mass) for ethanoic (acetic) acid is
CH2COOH
C x 2 = 12 x 2 = 24
H x 4 = 1 x 4 = 4
O x 2 = 16 x 2 = 32
24 + 4 + 32 = 60 ( The Mr ( Ethanoic acid) )
Substituting
moles = 458.77 g / 60 = 7.6461666.... moles
moles ~ 7.65 ( 2 d.p.)
lenpollock
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