0.5
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
To determine the grams of CO2 produced from 2.5 moles of O2, we first need to consider the balanced chemical equation for the combustion of a hydrocarbon (e.g., methane): CH4 + 2O2 → CO2 + 2H2O. From this equation, 2 moles of O2 produce 1 mole of CO2. Therefore, 2.5 moles of O2 would produce 1.25 moles of CO2. Since the molar mass of CO2 is approximately 44 grams/mol, 1.25 moles of CO2 corresponds to 55 grams (1.25 moles × 44 g/mol).
When 1 mole of C8H18 is burned, it forms 8 moles of CO2. Therefore, when 451 moles of C8H18 is burned, it will form 8 * 451 = 3608 moles of CO2.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.
19
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
44.0095
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 167 mole of CO2 has 167 mole of carbon atoms.
The answer is 4,1 CO2 moles.