First you need to know the molecular mass of the compound. The molecular mass is the sum of the atomic masses of each atom in the molecule. This means that you need to count atoms of the same element each time they occur in the compound.
Carbon = 12.0 × 5 atoms = 60.0 grams
Hydrogen = 1.0 × 12 atoms = 12.0 grams
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Pentane = 72.0 grams
Now we take the mass in grams and convert it to moles using the formula:
# grams ÷ molecular mass = # moles
220 g ÷ 72.0 g = 3.06 moles pentane
3.06
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
5.60 g C6H12O6 (1 mole C6H12O6/180.156 g)(6 moles C/1 mole C6H12O6)(6.022 X 1023/1 mole C) = 1.12 X 1023 atoms of carbon ======================
The answer is 2,17 moles carbon.
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
1,4 moles carbon monoxide are produced.
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
5.60 g C6H12O6 (1 mole C6H12O6/180.156 g)(6 moles C/1 mole C6H12O6)(6.022 X 1023/1 mole C) = 1.12 X 1023 atoms of carbon ======================
C6H1206 has 6 Carbon atoms, 12 Hydrogen atoms, and 6 Oxygen atoms, otherwise known as Glucose, a plant food made for long-term storage. Sorry if that's not what you're looking for! Added: This is what you are looking for. 300 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 mole C/1 mole C6H12O6)(6.022 X 10^23/1 mole C)(1 mole C/6.022 X 10^23) = 9.99 moles Carbon atoms in that mass glucose 300 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(12 mole H/1 mole C6H12O6)(6.022 X 10^23/1 mole H)(1 mole H/6.022 X 10^23) = 19.98 moles Hydrogen atoms in that mass glucose Now, you have seen two examples of this procedure, so you do the oxygen number crunching.
The answer is 2,17 moles carbon.
How many moles of C are needed to react with 0.490 mole SO2?
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
1,4 moles of CO are produced.
Use stoichiometry to convert grams of Carbon to moles of carbon and solve. 28093g C *(1mol C/12.011g C)= 2338.94mol C
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
1,4 moles carbon monoxide are produced.
4,37.10e-18 C atoms are equivalent to 7,25.10e-6 moles.
This is a chemical calculation. 2.5 moles will C reacting with O2.