1.4 moles - the HCl is the limiting ingredient
4 moles
NaNO3+CaCl2->NaCl+Ca(NO3)2
1 mole NaCl = 58.443g NaCl 234g NaCl x 1mol NaCl/58.443g NaCl = 4.00 moles NaCl
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
100 moles of NaCl
4 moles
-486kj
Any reaction between salt and water; salt is easily dissolved.
The correct term is neutralization reaction.
NaNO3+CaCl2->NaCl+Ca(NO3)2
AgNO3 + NaCl ===> AgCl(s) + NaNO37 moles silver nitrate will produce 7 moles of silver chloride provided there is sufficient (at least 7 moles) of sodium chloride.
The answer is 0,96 moles.
1 mole NaCl = 58.443g NaCl 234g NaCl x 1mol NaCl/58.443g NaCl = 4.00 moles NaCl
Molarity = moles of solute/liters of solution ( 50 ml = 0.05 liters ) 2.50 Molar NaCl = moles NaCl/0.05 liters solution = 0.125 moles NaCl ( 7.305 grams NaCl )
Any reaction between NaCl and H.
Sodium chloride, common salt. NaOH + HCl = NaCl + H2O
This reaction is:NaOH + HCl = NaCl + H2O