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Q: What is the reaction and change in enthalpy for the decomposition of 2 moles of NaCl?
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What is the difference between enthalpy change and enthalpy change per mole?

Enthalpy is the energy absorbed or lost from a reaction, but enthalpy change per mole is the amount of energy lost per mole, so in order to get the overall enthalpy from the change per mole, you must multiply that value by the amount of moles used in the reaction.


How much heat will be released when 6.44 grams of sulfur reacts with excess iron oxide?

You need to know the ∆H of this reaction, or the enthalpy change. If you know the enthalpy change, then convert the 6.44 g of sulfur to moles, and use stoichiometry to determine what fraction of a mole was reacted, and multiply that time the value of ∆H of the reaction


What is the correct heat of reaction for the composition of two moles of water?

This enthalpy of reaction is 560 joules, for liquid water at 25 oC.


How much heat is absorbed when 3.20 moles of A of react?

The answer to this question will depend on what the substance that is reacting is. You will need to find the appropriate standard enthalpy value, which corresponds to the amount of enthalpy change when one mole of matter is transformed by a chemical reaction in standard conditions.


How many moles of O2 are produced when 0.400 mol of KO2 reacts in this fashion?

The thermal decomposition reaction is:2 KO2------------K2O2 + O20,2 moles of O2 are produced from o,4 moles KO2.


Do chemical reactions that increase entropy tend to occur spontaneously?

Reactions that increase the randomness. Reactions that have more moles of gas on the product side than the reactant side increase entropy. Also reactions that have a positive change in spontaneity and a negative enthalpy.


How many moles of bromine will be formed upon the complete reaction of 0.248 moles bromine trifluoride?

The complete decomposition reaction is as follows:2 BrF3 → Br2 + 3 F2 , so 2 moles BrF3 will give 1 mole Br2 , hence 0.248 mole gives 0.124 mole Br2


What is the basic difference between enthalpy of formation?

Standard Heat (Enthalpy) of Formation, Hfo, of any compound is the enthalpy change of the reaction by which it is formed from its elements, reactants and products all being in a given standard state.By definition, the standard enthalpy (heat) of formation of an element in its standard state is zero, Hfo = 0.Standard Molar Enthalpy (Heat) of Formation, Hmo, of a compound is the enthalpy change that occurs when one mole of the compound in its standard state is formed from its elements in their standard states.Standard Enthalpy (Heat) of Reaction, Ho, is the difference between the standard enthalpies (heats) of formation of the products and the reactants.Ho(reaction) = the sum of the enthalpy (heat) of formation of products - the sum of the enthalpy (heat) of formation of reactants: Ho(reaction) = Hof(products) - Hof(reactants)To calculate an Enthalpy (Heat) of Reaction:Write the balanced chemical equation for the reaction Remember to include the state (solid, liquid, gas, or aqueous) for each reactant and product.Write the general equation for calculating the enthalpy (heat) of reaction: Ho(reaction) = Hof(products) - Hof(reactants)Substitute the values for the enthalpy (heat) of formation of each product and reactant into the equation. Remember, if there are 2 moles of a reactant or product, you will need to multiply the enthalpy term by 2, if molar enthalpies (heats) of formation are used.Standard Enthalpy (Heat) of FormationExample: Standard Enthalpy (Heat) of Formation of WaterThe standard enthalpy (heat) of formation for liquid water at 298K (25o) is -286 kJ mol-1. This means that 286 kJ of energy is released when liquid water, H2O(l), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(l) Hfo = -286 kJ mol-1The standard enthalpy (heat) of formation of water vapour at 298K (25o) is -242 kJ mol-1.This means that 242 kJ of energy is released when gaseous water (water vapour), H2O(g), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(g) Hfo = -242 kJ mol-1


What information do you need to determine how a change in pressure will affect the equilibrium of a reaction?

The total number of moles of gas on each side of the reaction.


How many moles of potassium chlorate are needed to produce 15 moles of oxygen?

Assuming a decomposition reaction with this equation: 2KClO3(s) --> 2KCl(s) + 3O2(g), the ratio is 2:3, and if you produce 15mol O2, then 10mol potassium chlorate are needed.


Why is the enthalpy of reaction between sodium hydroxide and sulfuric acid different from that of sodium hydroxide and hydrochloric acid?

sulphuric acid is a diprotic acid so has two H+ and needs two moles of sulphuric acid to neutralise it


What is 2h2o2?

O2 is an oxygen molecule, H2O is a water molecule. The 2 in front of each means that you have 2 moles of each