To do this, you need to know the molecular weight of the element you're dealing with, by adding up the atomic weights of the elements involved (found on any Periodic Table). The molecular weight is the mass in grams of the compound in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the molecular weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the molecular weight. That's the thought process behind unit analysis and how you get your "units to cancel".
In this case, the answer is about .25 moles O2.
The answer is 4,09 moles.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
4 NH3 + 5 O2 ---> 4 NO + 6 H2Omoles NH3 used = 36.3 g x 1 mole/17 g = 2.14 molesmoles O2 needed = 2.14 moles (note a 1mole to 1mole ratio of O2 to NH3 in balanced equation)grams O2 needed = 2.14 moles x 32g/mol = 68.48 grams needed
:Mg: (2.43 g)/(24.3 g/mol) = .1 mol :MgO: (.1 mol)(24.3+16.0 g/mol) = 4.03 g
1 mole of 02 gas has 12,044 281 714.1023 atoms.
Molarity = moles of solute/Liters of solutionMoles of solute = Liters of solution * Molarity ( 100 mL = 0.1 Liters )Moles of NaCl = 0.1 Liters * 0.20 M NaCl= 0.02 moles NaCl============
15 moles of 02 equal 480 g.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
The answer is 1,72 moles.
I assume you mean this reaction. 2Mg + O2 --> 2MgO 16 or 160 ??? Either way the form is the same. We will use the 16 grams. 16 g O2 (1 mole O2/32 grams)(2 mole Mg/1 mole O2) = 1.0 mole magnesium needed ======================
.02 grams there are 1000 mg in a gram. so divide 20 by 1000 to get .02
.02
First you want to think "if I had 100 grams of this compound". If you do this, then you will be able to use the percentages as measurements in grams. Completing the sentence: "if I had 100 grams of this compound, then I would have 26 grams of nitrogen and 74 grams of oxygen". The next step is converting the grams to moles.Grams ÷ Atomic weight = moles26.0 grams ÷ 14.0 grams = 1.86 moles N74.0 grams ÷ 16.0 grams = 4.63 moles OThis is a ratio of 1.86:4.63 and is not recognizable as a small whole number ratio. (If this doesn't make sense, see the Law of Definite Proportions). In order to make the two numbers whole numbers, a trick is to divide both by the smallest number. Doing this will ensure that one number will always be 1.1.86 moles N ÷ 1.86 = 14.63 moles O ÷ 1.86 = 2.49Because the last digit is always uncertain to .02, we can say that 2.49 is actually 2.5. Now your ratio is 1:2.5, yet these are still not whole numbers. When you have an increment of .5, then multiply everything by 2.1:2.5 × 2 = 2:5 or 2 nitrogen : 5 oxygenYour final answer is N2O5
4 NH3 + 5 O2 ---> 4 NO + 6 H2Omoles NH3 used = 36.3 g x 1 mole/17 g = 2.14 molesmoles O2 needed = 2.14 moles (note a 1mole to 1mole ratio of O2 to NH3 in balanced equation)grams O2 needed = 2.14 moles x 32g/mol = 68.48 grams needed
To determine how many atoms are present in 56 liters of oxygen gas at STP you first need to know that there are two atoms in a single molecule. Then, you would work the scientific formula to determine the number of molecules in the oxygen gas.
Ten milliliters is a hundredth of a liter. So in a two molar solution, you would have .02 moles in 10 ml.
an o2 sensor is the same as an oxygen sensor. vehicles can have up to 4