To do this, you need to know the molecular weight of the element you're dealing with, by adding up the atomic weights of the elements involved (found on any Periodic Table). The molecular weight is the mass in grams of the compound in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the molecular weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the molecular weight. That's the thought process behind unit analysis and how you get your "units to cancel".
In this case, the answer is about .25 moles O2.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
4 NH3 + 5 O2 ---> 4 NO + 6 H2Omoles NH3 used = 36.3 g x 1 mole/17 g = 2.14 molesmoles O2 needed = 2.14 moles (note a 1mole to 1mole ratio of O2 to NH3 in balanced equation)grams O2 needed = 2.14 moles x 32g/mol = 68.48 grams needed
Using the balanced chemical equation: 2Mg + O2 -> 2MgO, we can see that 1 mol of O2 reacts with 2 moles of Mg to produce 2 moles of MgO. Calculate the moles of O2: 40g O2 / 32g/mol = 1.25 mol O2 From the equation, 1.25 mol O2 will produce 2.5 mol of MgO. Calculate the grams of MgO produced: 2.5 mol MgO * 40.3 g/mol = 100.75 grams MgO.
1 mole of 02 gas has 12,044 281 714.1023 atoms.
Molarity = moles of solute/Liters of solutionMoles of solute = Liters of solution * Molarity ( 100 mL = 0.1 Liters )Moles of NaCl = 0.1 Liters * 0.20 M NaCl= 0.02 moles NaCl============
15 moles of 02 equal 480 g.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
The answer is 1,72 moles.
The molar mass of sulfur (S) is approximately 32 g/mol. Therefore, 5.35 grams of S is equal to 5.35/32 = 0.167 moles of S. The balanced chemical equation for the reaction of sulfur with oxygen is given by 2S + 3O2 → 2SO3, which means 3 moles of O2 are needed to react with 2 moles of S. Hence, for 0.167 moles of S, we would need (3/2) * 0.167 = 0.2505 moles of O2, which is equivalent to 0.2505 * 6.022 x 10^23 = 1.51 x 10^22 molecules of O2.
The balanced chemical equation for the reaction between magnesium and oxygen is 2Mg + O2 → 2MgO. It shows that 1 mole of Mg reacts with 1 mole of O2. The molar mass of Mg is 24.31 g/mol, and O2 is 32.00 g/mol. First, calculate the number of moles of O2 in 16g, then use the mole ratio from the balanced equation to find the moles of Mg, and finally convert to grams.
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. Since 11.2 liters represent half the volume of a mole, we have 0.5 moles of O2 gas. Using the molar mass of oxygen (O2), which is around 32 g/mol, we find that 0.5 moles of O2 gas would be equivalent to approximately 16 grams.
.02 grams there are 1000 mg in a gram. so divide 20 by 1000 to get .02
.02
4 NH3 + 5 O2 ---> 4 NO + 6 H2Omoles NH3 used = 36.3 g x 1 mole/17 g = 2.14 molesmoles O2 needed = 2.14 moles (note a 1mole to 1mole ratio of O2 to NH3 in balanced equation)grams O2 needed = 2.14 moles x 32g/mol = 68.48 grams needed
First you want to think "if I had 100 grams of this compound". If you do this, then you will be able to use the percentages as measurements in grams. Completing the sentence: "if I had 100 grams of this compound, then I would have 26 grams of nitrogen and 74 grams of oxygen". The next step is converting the grams to moles.Grams ÷ Atomic weight = moles26.0 grams ÷ 14.0 grams = 1.86 moles N74.0 grams ÷ 16.0 grams = 4.63 moles OThis is a ratio of 1.86:4.63 and is not recognizable as a small whole number ratio. (If this doesn't make sense, see the Law of Definite Proportions). In order to make the two numbers whole numbers, a trick is to divide both by the smallest number. Doing this will ensure that one number will always be 1.1.86 moles N ÷ 1.86 = 14.63 moles O ÷ 1.86 = 2.49Because the last digit is always uncertain to .02, we can say that 2.49 is actually 2.5. Now your ratio is 1:2.5, yet these are still not whole numbers. When you have an increment of .5, then multiply everything by 2.1:2.5 × 2 = 2:5 or 2 nitrogen : 5 oxygenYour final answer is N2O5
20 milligrams is zero teaspoon. There are 4.67 grams in a teaspoon, therefore .02 grams is not a teaspoon.