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How many moles of PCl5 can be produced from 56.0g Cl2 and excess P4?
Wiki User
∙ 13y ago
To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.
Wiki User
∙ 9y ago
Wiki User
∙ 12y ago55.0 g of Cl2 contains 55.0/35.45* or 1.551 gram atoms of chlorine. Each mole of PCl5 requires exactly 5 gram atoms of chlorine, as shown by the formula. Therefore, 1.551/5.000 or 0.310 moles of PCl5 can be formed, to the justified number of significant digits.
*This number is the gram Atomic Mass of chlorine.
Wiki User
∙ 13y agoBalanced equation.
2P + 5Cl2 -> 2PCl5
56.0 grams Cl2 (1 mole Cl2/70.9 grams)(2 mole PCl5/5 moles Cl2)
= 0.316 moles PCl5 produced
Wiki User
∙ 9y agoThe molar mass of Cl2 is 5.1 g/mol. If there is 51.0 g of Cl2 then there are 10 moles. 10 moles of Cl2 can produce 4 moles of PCl5.
Wiki User
∙ 11y ago0.839
Wiki User
∙ 11y ago0.288 mole
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What mass of PCl 5 will be produced from the given masses of both reactants?
What mass of will be produced from the given masses of both reactants? 28.0 g/P4 / 123.9 g/P4 = 0.2260 moles/ P4 0.2260 moles /P4 * 4 moles PCl5/1 mole/P4=0.904 moles/PCl5 54.0 g/Cl2 / 70.9 g/Cl2 = .7616 moles/Cl2 .7616 moles / Cl2 *4 moles PCl5/10 moles Cl2=.30 This is about limiting reagents You need to use 2P + 5Cl2 --> 2PCl5 [or P4 + 10Cl2 --> 4PCl5 if you prefer] that tells you that 2P = 62g needs 5Cl2 = 355g Cl2 to react 69.3g
What mass of PCl5 will be produced from the given masses of both reactants which is 839 moles of P4 and 316 moles of Cl2 Answer needs to be submitted in grams though please?
Our lower number of moles is .316 so we will use that. The total molar mass of PCl5 is 208.2. So we will multiply the lower number of moles by our total mass. .316mol X 208.2 g/mol = 65.8g <------ answer.
How many moles of PCl5 can be produced from 24 grams of P4?
Assuming that you are combining the P4 with Cl2 and there is a suffiecient quantity of Cl2 for the P4 to completely react, you will first need a balanced equation which is P4 + 10Cl2 -> 4PCl5. From there, it's mostly stoichiometry. Take the 24g of P4, divide by the molar mass (123.88g/mol) to get the number of moles of P4 that you have (0.194). You then have to convert, using the balanced equation, from moles of P4 to moles of PCl5, in this case multiplying by 4. That will give you the number of moles of PCl5. The stoichiometry should look something like this 24.0 g P4 x (1 mol P4/123.88g P4) x (4 mol PCl5/1 mol P4).
What is chloropentane?
Chlorohexane which is also known as hexyl chloride is a halogened hydrocarbon which can be produced by treating 1-heaxnol with fuming HCl or with excess SOCl2 or with PCl5 and ZnCl2.
What is the name of PCl5 compound?
The name of the compound PCl5 is phosphorus pentachloride.
How many moles of PCl5 can be produced from 55.0 g of Cl2 (and excess P4)?
55.0 g of Cl2 contains 55.0/35.45* or 1.551 gram atoms of chlorine. Each mole of PCl5 requires exactly 5 gram atoms of chlorine, as shown by the formula. Therefore, 1.551/5.000 or 0.310 moles of PCl5 can be formed, to the justified number of significant digits. *This number is the gram Atomic Mass of chlorine.
What mass of PCl 5 will be produced from the given masses of both reactants?
What mass of will be produced from the given masses of both reactants? 28.0 g/P4 / 123.9 g/P4 = 0.2260 moles/ P4 0.2260 moles /P4 * 4 moles PCl5/1 mole/P4=0.904 moles/PCl5 54.0 g/Cl2 / 70.9 g/Cl2 = .7616 moles/Cl2 .7616 moles / Cl2 *4 moles PCl5/10 moles Cl2=.30 This is about limiting reagents You need to use 2P + 5Cl2 --> 2PCl5 [or P4 + 10Cl2 --> 4PCl5 if you prefer] that tells you that 2P = 62g needs 5Cl2 = 355g Cl2 to react 69.3g
What mass of PCl5 will be produced from the given masses of both reactants which is 839 moles of P4 and 316 moles of Cl2 Answer needs to be submitted in grams though please?
Our lower number of moles is .316 so we will use that. The total molar mass of PCl5 is 208.2. So we will multiply the lower number of moles by our total mass. .316mol X 208.2 g/mol = 65.8g <------ answer.
How many moles of PCl5 can be produced from 24 grams of P4?
Assuming that you are combining the P4 with Cl2 and there is a suffiecient quantity of Cl2 for the P4 to completely react, you will first need a balanced equation which is P4 + 10Cl2 -> 4PCl5. From there, it's mostly stoichiometry. Take the 24g of P4, divide by the molar mass (123.88g/mol) to get the number of moles of P4 that you have (0.194). You then have to convert, using the balanced equation, from moles of P4 to moles of PCl5, in this case multiplying by 4. That will give you the number of moles of PCl5. The stoichiometry should look something like this 24.0 g P4 x (1 mol P4/123.88g P4) x (4 mol PCl5/1 mol P4).
How many moles of PCl5 are in 35.6 g of PCl5?
Molar mass = 31+ 5(35.5) = 208.5 g/mole divide ... 35.6 g / 208.5 g/mole = 0.171 mole
What is chloropentane?
Chlorohexane which is also known as hexyl chloride is a halogened hydrocarbon which can be produced by treating 1-heaxnol with fuming HCl or with excess SOCl2 or with PCl5 and ZnCl2.
What is the formula for the molecular compound phosphorus pentachloride?
PCl5 Phosphorous pentachlorideP for Phosphorous and 5 Cl for chloride= PCl5 College Chemistry student
What is the for PCl5?
Phosphorus pentachloride (PCL5)
What is the name of PCl5 compound?
The name of the compound PCl5 is phosphorus pentachloride.
What is the decomposition reaction for PCl5?
PCl5 -----> PCl3 + Cl2
Is PCl5 an electrolyte?
Yes, PCl5 is a binary molecular compound.
What gas is produced by mixing chlorine and alcohol?
No gas is produced. Chlorine does not react with alcohol. Alcohols can be chlorinated using PCl5, SOCl3, PCl3, in such reaction form white fumes of HCl.
