The answer is 6,482 moles.
How many moles of atoms are contained in 382 g Co
1 mole Co = 58.933g Co (atomic weight in grams)1 mole Co atoms = 6.022 x 1023 atoms CoConvert grams Co to moles Co.22.6g Co x (1 mole Co/58.933g) Co = 0.383 mole CoConvert mole Co to atoms Co.0.383 mole Co x (6.022 x 1023 atoms Co/1 mole Co) = 2.31 x 1023 atoms Co
1,4 moles of CO are produced.
no
2,55 moles of the compound CO have 71,4 grams.
382 g Co contain 6,482 moles.
How many moles of atoms are contained in 382 g Co
1 mole Co = 58.933g Co (atomic weight in grams)1 mole Co atoms = 6.022 x 1023 atoms CoConvert grams Co to moles Co.22.6g Co x (1 mole Co/58.933g) Co = 0.383 mole CoConvert mole Co to atoms Co.0.383 mole Co x (6.022 x 1023 atoms Co/1 mole Co) = 2.31 x 1023 atoms Co
I think you would take the 6 billion atoms and divide it by Avogadro's number which is the number of atoms in a mole of a element by definition. I don't remember the value of that number but someone will.
1,4 moles of CO are produced.
4,54 L of CO have 0,182 moles.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
no
2,55 moles of the compound CO have 71,4 grams.
Assuming you meant Carbon monoxide (CO): (1.5)* (6.02*10^23) = 9.03*10^23 molecules CO That could be written as: 903,000,000,000,000,000,000,000 molecules
26,3 g cobalt is equivalent to 0,446 moles.
5.34 grams W(CO)6 (1 mole W(CO)6/351.86 grams)(6 moles C/1 mole W(CO)6)(6.022 X 1023/1 mole C) = 5.48 X 1022 atoms of carbon ========================